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lina2011 [118]
3 years ago
8

URGENT!!!!!!!!!!11!! Plz HElP

Mathematics
1 answer:
riadik2000 [5.3K]3 years ago
3 0
The answer is a=100 and b=5
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How to comment on brainly.com and I'm only 8-years-old so keep it simple please
dedylja [7]

Answer:

You just do.

Step-by-step explanation:

That's all there is

8 0
2 years ago
I need help it's geometry
nekit [7.7K]

Step-by-step explanation:

\sin(45)  =  \frac{x}{5}  \\   \frac{1}{ \sqrt{2} } =  \frac{x}{5}    \\ x =  \frac{5}{ \sqrt{2} }  = 3.535

\sin(45)  =  \frac{y}{5}  \\ y =  \frac{5}{ \sqrt{2} }  = 3.535

3 0
3 years ago
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What is the perimeter of a polygon with the vertices at (-2,1) (-2,4) (2,7) (6,4) (6,1)?
rusak2 [61]

Answer:

24

Step-by-step explanation:

3 0
3 years ago
The square of a number minus six times a number equals negative five.
olga_2 [115]

Answer:

x² - 6x = -5

x = {1, 5}

Step-by-step explanation:

The square of a number minus six times a number equals negative five.

x² - 6x = -5

Add 5 to both sides

x² - 6x + 5 = 0

Factor

(x - 1)(x - 5) = 0

x = {1, 5}

3 0
3 years ago
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Please answer correctly !!!!!!! Will mark brainliest !!!!!!!!!!!!
LUCKY_DIMON [66]

Answer:

=8\sqrt{15}b^{\frac{7}{2}}

Step-by-step explanation:

\sqrt{24b^3}\sqrt{40b^2}\sqrt{b^2}

=\sqrt{40}\sqrt{b^2}\sqrt{b^2}\sqrt{24b^3}

=\sqrt{40}b^2\sqrt{24b^3}

\sqrt{24b^3}

=\sqrt{24}\sqrt{b^3}

=\sqrt{24}b^{\frac{3}{2}}

=\sqrt{24}b^{\frac{3}{2}}\sqrt{40}b^2

=\sqrt{2^3\cdot \:3}b^{\frac{3}{2}}\sqrt{40}b^2

=\sqrt{2^3}\sqrt{3}b^{\frac{3}{2}}\sqrt{40}b^2

\sqrt{2^3}

=2^{3\cdot \frac{1}{2}

=2^{3\cdot \frac{1}{2}}\sqrt{3}b^{\frac{3}{2}}\sqrt{40}b^2

=2^{\frac{3}{2}}\sqrt{3}b^{\frac{3}{2}}\sqrt{40}b^2

=2^{\frac{3}{2}}\sqrt{3}b^{\frac{3}{2}}\sqrt{2^3\cdot \:5}b^2

=2^{\frac{3}{2}}\sqrt{3}b^{\frac{3}{2}}\sqrt{2^3}\sqrt{5}b^2

=2^{\frac{3}{2}}\sqrt{3}b^{\frac{3}{2}}\cdot \:2^{\frac{3}{2}}\sqrt{5}b^2

=\sqrt{3}b^{\frac{3}{2}}\cdot \:2^{\frac{3}{2}+\frac{3}{2}}\sqrt{5}b^2

=\sqrt{3}\cdot \:2^{\frac{3}{2}+\frac{3}{2}}\sqrt{5}b^{\frac{3}{2}+2}

2^{\frac{3}{2}+\frac{3}{2}}

=2^3

=2^3\sqrt{3}\sqrt{5}b^{\frac{3}{2}+2}

b^{\frac{3}{2}+2}

=b^{\frac{7}{2}}

=2^3\sqrt{3}\sqrt{5}b^{\frac{7}{2}}

=2^3\sqrt{3\cdot \:5}b^{\frac{7}{2}}

=8\sqrt{15}b^{\frac{7}{2}}

4 0
3 years ago
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