Answer:
ask the internet this question sorry not being rude its becausd no ones answered it
Answer:
by 3% percent
Step-by-step explanation:
i hope this helps ._.
Answer:
240
Step-by-step explanation:
Answer:
B. 2/3
Step-by-step explanation:
To solve this we have to take into account this axioms:
- The total probability is always equal to 1.
- The probability of a randomly selected point being inside the circle is equal to one minus the probability of being outside the circle.
Then, if the probabilities are proportional to the area, we have 1/3 probability of selecting a point inside a circle and (1-1/3)=2/3 probability of selecting a point that is outside the circle.
Then, the probabilty that a random selected point inside the square (the total probability space) and outside the circle is 2/3.
F(x)=3x2-11
f(5)=6-11
5f=-5
5f/5=-5/5
f=-1