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Korolek [52]
3 years ago
13

Determine which type of transformation is illustrated in the figure. If none of the listed transformations apply, choose

Mathematics
1 answer:
erik [133]3 years ago
4 0
The picture of the question provided is non-existent
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If i have three rolls of a dice and for the first and second you choose to either keep your roll or keep going, what is the best
AleksAgata [21]

Answer:

  • On the first roll, we keep a result of 5 or 6, and roll again if it is 4 or lower
  • On the second roll, we keep any result equal or greater that 4 and we roll again for 1,2 or 3
  • We keep anything we obtained from the third row

The expected value is 14/3 = 4.666

Step-by-step explanation:

When you throw a roll the expected value is 3.5 (the average of 1,2,3,4,5 and 6). This means that any roll with value 3 or below is worth changing, because the expected value will transform into 3.5 from the 3 or less you had before.

This means that in your second roll you will keep the result as long as it is 4 or more and you will roll once more if it is 3 or less, hence, you can

  • get a 4, 5 and 6 on your second roll and keep it, so that your value is that number
  • get 1, 2 or 3 on your second roll and roll again, with an expected value of 3.5.

Rolling a third time has a probability of 3/6 = 0.5, obtaining a 4 has a probability of 1/6, same for 5 and 6. Thus, the expected value from the second roll onwards is

1/2 * 3.5 + 1/6 * 4 + 1/6 * 5 + 1/6 * 6 = 4.25

This means that, after the first roll, we can keep that value or throw again with an expected value of 4.25 (using the strategy depicted above). We can roll again if we got a result of 4 or below expecting a higher value or keep a result of 5 or 6.

The strategy can be ssummarized as follows

  • On the first roll, we keep a result of 5 or 6, and roll again if it is 4 or lower
  • On the second roll, we keep any result equal or greater that 4 and we roll again for 1,2 or 3
  • We keep anything we obtained from the third row

The probability of getting 4 or below is 4/6 = 2/3, and the expected value for the second roll onwards is 4.25, hence the expected value of the strategy we pick is

1/6 * 5 + 1/6*6 + 2/3* 4.25 = 4.666 = 14/3

8 0
3 years ago
Please urgent!!!!!!!!!!!!
Rus_ich [418]

Answer:

the last one

Step-by-step explanation:

6 0
2 years ago
The cost of 4 cookies, 6 doughnuts, and 3 boxes of doughnut holes is $8.15. The cost of 2 cookies, 3 doughnuts, and 4 boxes of d
Naddika [18.5K]

Answer:

$1.25

Step-by-step explanation:

This can best be determined using a set of linear equations that are solved simultaneously.

This pair of linear equations may be solved simultaneously by using the elimination method. This will involve ensuring that the coefficient of one of the unknown variables is the same in both equations.

Let the cost of a cookie be c, cost of a doughnut be d and that of a box of doughnut hole be h then if cost of 4 cookies, 6 doughnuts, and 3 boxes of doughnut holes is $8.15, we have

4a + 6d + 3h = 8.15

and the cost of 2 cookies, 3 doughnuts, and 4 boxes of doughnuts holes is $7.20 then

2a + 3d + 4h = 7.20

Dividing the first by 2

2a + 3d + 1.5h = 4.075

subtracting from the second equation

2.5h = 3.125

h = 1.25

The cost of a box of doughnut holes is $1.25

5 0
2 years ago
Picture down there Thanksssss
maria [59]
Im pretty sure there is 145 students
7 0
3 years ago
Read 2 more answers
QUICKLY HELP! Which relationship between x and y in the equation shows a proportional relationship?
Darina [25.2K]
Y = 12x is a direct variation which is a proportion.
As x increases y also increases.
3 0
3 years ago
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