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taurus [48]
3 years ago
5

What is a factor of 12

Mathematics
1 answer:
Ymorist [56]3 years ago
3 0

Answer:

2 x 3 (prime number, 2 distinct)

Step-by-step explanation:

You might be interested in
Evaluate the expression 7+3²× 2​
disa [49]

Answer:

25

Step-by-step explanation:

6 0
3 years ago
A. Sam purchased 3 games for $140 after a discount of 30%. What was the original price?
Semmy [17]

Answer:

a) $175 b) It will be $126

Step-by-step explanation:

Cost price of 3 games= $140

Let the original price of games= $ x

Discount is given= 30%

According to question

x \frac{(100-20)}{100}= $140

x \frac{80}{100}= $140

x ×0.8= $140

x= $ \frac{$140}{0.8}

x= $175

Hence, the original price of games $ 140

(b)  If Sam had given a discount of 20%

Again a discount = 10%

The price of games=$ 140

Now, the selling price will be= 175\frac{(100-20)}{100}×\frac{(100-10)}{100}

Now, the selling price will be= $ 126

Hence, the price will be different.

7 0
3 years ago
A) How many ways can 2 integers from 1,2,...,100 be selected
Anna007 [38]

Answer with explanation:

→Number of Integers from 1 to 100

                                            =100(50 Odd +50 Even)

→50 Even =2,4,6,8,10,12,14,16,...............................100

→50 Odd=1,3,,5,7,9,..................................99.

→Sum of Two even integers is even.

→Sum of two odd Integers is odd.

→Sum of an Odd and even Integer is Odd.

(a)

Number of ways of Selecting 2 integers from 50 Integers ,so that their sum is even,

   =Selecting 2 Even integers from 50 Even Integers , and Selecting 2 Odd integers from 50 Odd integers ,as Order of arrangement is not Important, ,

        =_{2}^{50}\textrm{C}+_{2}^{50}\textrm{C}\\\\=\frac{50!}{(50-2)!(2!)}+\frac{50!}{(50-2)!(2!)}\\\\=\frac{50!}{48!\times 2!}+\frac{50!}{48!\times 2!}\\\\=\frac{50 \times 49}{2}+\frac{50 \times 49}{2}\\\\=1225+1225\\\\=2450

=4900 ways

(b)

Number of ways of Selecting 2 integers from 100 Integers ,so that their sum is Odd,

   =Selecting 1 even integer from 50 Integers, and 1 Odd integer from 50 Odd integers, as Order of arrangement is not Important,

        =_{1}^{50}\textrm{C}\times _{1}^{50}\textrm{C}\\\\=\frac{50!}{(50-1)!(1!)} \times \frac{50!}{(50-1)!(1!)}\\\\=\frac{50!}{49!\times 1!}\times \frac{50!}{49!\times 1!}\\\\=50\times 50\\\\=2500

=2500 ways

7 0
3 years ago
Which system of linear inequalities is represented by the graph?
Zarrin [17]

Answer:

The linear inequality is represented by y < x _ 2 and y > x + 1

6 0
2 years ago
Read 2 more answers
Which of the following points lies in the solution set to the system of inequalities shown below
Oduvanchick [21]

Answer:

1,2, and 4

Step-by-step explanation:

I attached a picture with the graph

y= -4 is a straight horizontal line (red line) and  

y≤10 will give a horizontal line passing trough y=10 (blue line)

the solution is all points under and on the line  y=10

1, 2, and 4 are part of the solution set

(the blue area is the solution of the system of equations)

7 0
3 years ago
Read 2 more answers
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