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Ratling [72]
3 years ago
13

NEED HELP! What is the first step to solve the equation a=2d/t^2 , where a is acceleration, d is the distance, and t is time. If

an object accelerates at a rate of 2(m/s^2) for 10 meters, what is the total time elapsed?

Mathematics
1 answer:
kondor19780726 [428]3 years ago
8 0

Plug in <em>a</em> = 2 m/s^2 and <em>d</em> = 10 m, and solve for <em>t</em> (in s):

a=\dfrac{2d}{t^2}\iff2\dfrac{\rm m}{\mathrm s^2}=\dfrac{2\cdot10\,\mathrm m}{t^2}

\implies t^2=\dfrac{20\,\rm m}{2\frac{\rm m}{\mathrm s^2}}=10\,\mathrm s^2

\implies t=\sqrt{10}\,\mathrm s

So the answer is C.

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Answers

1) 1

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= (0 - -2)/(-4 - -6)

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3 years ago
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Answer:

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Step-by-step explanation:

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__________________________________________________

Given

one endpoint is (–6, 4) and midpoint is (–2, 7)

let coordinates of other endpoint be (x,y)

now if one endpoint is (–6, 4) and other endpoint is (x,y)

then coordinates of midpoint is ((-6+x)/2 , (4+y)/2)

while the coordinates of midpoint given  is  (–2, 7)

thus (–2, 7) should be equal to ((-6+x)/2 , (4+y)/2)

-2 = (-6+x)/2             and   7 = (4+y)/2

=> -2*2 = -6+x                 => 7*2 = 4+y

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=> -4+6 = x                     => 14-4 = y

=> x = 2                           => 10 = y

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