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3 years ago

Can someone help me with this? And please, actually try with this one.

Mathematics

2 answers:

kramer3 years ago

8 0

Answer:

my calculator says it is 105 then the middle thing then 16

SashulF [63]3 years ago

4 0

Answer:

32/3 or 10.6 repeating

Step-by-step explanation:

multiply by reciprocal

6*(16/9)

96/9

simplified to 32/3

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The volume of a cylinder is 176 π cm and its height is 11 π cm.

Liula [17]

Answer:

r = sqrt(16/pi)

Step-by-step explanation:

Cylinder formula = r^2 x pi x height

176 pi/11pi = 16

16 = r^2 x pi

16/ pi = r^2

r = sqrt(16/pi)

6 0

2 years ago

What is the VERTEX of the quadratic y = 2

RSB [31]

Answer:

The vertex is ( -4,1)

Step-by-step explanation:

The equation for a parabola can be written as

y = a( x-h)^2 +k where ( h,k) is the vertex

y = 2 (x + 4)² + 1

Rewriting

y = 2 (x - -4)² + 1

The vertex is ( -4,1)

4 0

3 years ago

Read 2 more answers

Identify the x-intercepts of the function below f(x)=x^2+12x+24

damaskus [11]

ANSWER:

x-intercepts of $\mathrm{x}^{2}+12 \mathrm{x}+24=0 \text { are }(-6+2 \sqrt{3}),(-6-2 \sqrt{3})$

SOLUTION:

Given, $f(x)=x^{2}+12 x+24$ -- eqn 1

x-intercepts of the function are the points where function touches the x-axis, which means they are zeroes of the function.

Now, let us find the zeroes using quadratic formula for f(x) = 0.

$X=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a}$

Here, for (1) a = 1, b= 12 and c = 24

$X=\frac{-(12) \pm \sqrt{(12)^{2}-4 \times 1 \times 24}}{2 \times 1}$

$\begin{array}{l}{X=\frac{-12 \pm \sqrt{144-96}}{2}} \\\\ {X=\frac{-12 \pm \sqrt{48}}{2}} \\\\ {X=\frac{-12 \pm \sqrt{16 \times 3}}{2}} \\\\ {X=\frac{-12 \pm 4 \sqrt{3}}{2}} \\ {X=\frac{2(-6+2 \sqrt{3})}{2}, \frac{2(-6-2 \sqrt{3})}{2}} \\\\ {X=(-6+2 \sqrt{3}),(-6-2 \sqrt{3})}\end{array}$