Can someone please put this in numerical order? Will give 15 points to who does!!!!!!
2 answers:
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Step-by-step explanation:
Our coordinates are (6, 0) and (0, -3).
We can use the formula (y₂-y₁)/(x₂-x₁) to find the slope-intercept form (y=mx+b)
Now, we plug the coordinates into the formula and solve.
(0-(-3))/(6-0)
=3/6
=
So, the slope is .
Now, we have to find the y-intercept, which is the point where the line on the graph intersects with the y-axis.
We can find the y-intercept (which is represented by b) by plugging the information we already know into the formula.
We can use either pair of coordinates for the formula, so I'll use (6, 0).
y=mx+b
0=(6)+b
Now, we can solve.
0=3+b
Subtract 3 from both sides.
-3=b
The y-intercept is -3.
Answer:
y=x-3
Answer:
x >= -7 ................(1a)
x >= 3 ...............(2a1)
Step-by-step explanation:
f(x) = .............(0)
find the domain.
To find the (real) domain, we need to ensure that each term remains a real number.
which means the following conditions must be met
x+7 >= 0 .....................(1)
AND
x^2+2x-15 >= 0 ..........(2)
To satisfy (1), x >= -7 .....................(1a) by transposition of (1)
To satisfy (2), we need first to find the roots of (2)
factor (2)
(x+5)(x-3) >= 0
This implis
(x+5) >= 0 AND (x-3) >= 0.....................(2a)
OR
(x+5) <= 0 AND (x-3) <= 0 ...................(2b)
(2a) is satisfied with x >= 3 ...............(2a1)
(2b) is satisfied with x <= -5 ................(2b1)
Combine the conditions (1a), (2a1), and (2b1),
x >= -7 ................(1a)
AND
(
x >= 3 ...............(2a1)
OR
x <= -5 ................(2b1)
)
which expands to
(1a) and (2a1) OR (1a) and (2b1)
( x >= -7 and x >= 3 ) OR ( x >= -7 and x <= -5 )
Simplifying, we have
x >= 3 OR ( -7 <= x <= -5 )
Referring to attached figure, the domain is indicated in dark (purple), the red-brown and white regions satisfiy only one of the two conditions.
