Answer:
CI(99%) = ( 0.93 , 2.07)
Therefore at 99% confidence interval (a,b) = ( 0.93 , 2.07)
Critical value z(at 99% confidence) = z(0.005) = 2.58
Step-by-step explanation:
Confidence interval can be defined as a range of values so defined that there is a specified probability that the value of a parameter lies within it.
The confidence interval of a statistical data can be written as.
x+/-zr/√n
Given that;
Mean gain x = 1.5
Standard deviation r = 0.58
Number of samples n = 7
Confidence interval = 99%
Critical value z(at 99% confidence) = z((1-0.99)/2)
z(0.005) = 2.58
Substituting the values we have;
1.5+/-2.58(0.58/√7)
1.5+/-2.58(0.2192)
1.5+/-0.565536
1.5+/-0.57
= ( 0.93 , 2.07)
Therefore at 99% confidence interval (a,b) = ( 0.93 , 2.07)
Answer:
The area is 30
Step-by-step explanation:
because its length x width x height
There are 4 teams in total and each team has 7 members. One of the team will be the host team.
Tournament committee will be made from 3 members from the host team and 2 members from each of the three remaining teams. Selecting the members for tournament committee is a combinations problem. We have to select 3 members out 7 for host team and 2 members out of 7 from each of the remaining 3 teams.
So total number of possible 9 member tournament committees will be equal to:
![7C3 \times 7C2 \times 7C2 \times 7C2\\ \\ = 324135](https://tex.z-dn.net/?f=%207C3%20%5Ctimes%207C2%20%5Ctimes%207C2%20%5Ctimes%207C2%5C%5C%20%5C%5C%20%20%3D%20324135%20)
This is the case when a host team is fixed. Since any team can be the host team, there are 4 possible ways to select a host team. So the total number of possible 9 member tournament committee will be:
![9 \times 324135\\ \\ =2917215](https://tex.z-dn.net/?f=%209%20%5Ctimes%20324135%5C%5C%20%5C%5C%20%20%3D2917215%20)
Therefore, there are 2917215 possible 9 member tournament committees
Answer:
tenths.........
Step-by-step explanation:
.....is the answer