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4 years ago

Find each rate in 40 meters in 16 sec

1 answer:

4 0

Rate = 40/16 = 10/4 = 5/2 = 2.5 meters/second Unit rate = ratio where denominator is 1 = 2.5/1 meters/second

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Solve the system by substitution. Y = 6x-2 Y = 5x

rusak2 [61]

Answer:

x = 1/3 x=0

Step-by-step explanation:

y=6x-2

2=6x

2/6 = x

1/3=x

y=5x

5x=0

divide both sides by 5

0/5 = 0

8 0

3 years ago

Read 2 more answers

What is the square cube law?

viktelen [127]

Answer:

The square–cube law (or cube – square law) is a mathematical theory, implemented in a number of scientific contexts, which defines the relationship between the volume and the surface area as a shape 's size increases or decreases.

Hope this helps!

3 0

3 years ago

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In an attempt to escape a desert island, a castaway builds a raft and sets out to sea. The wind shifts a great deal during the d

nikdorinn [45]

Answer:

R = 7,34 km

Ф = 63,43° north of east

Step-by-step explanation:

Let´s analyze each movement and find its perpendicular components. Then, we are going to add the components along the x and y axes to get the resultant and finally to calculate its magnitude and direction.

To determine the perpendicular components, we will use right triangles trigonometrics ratios.

Please see images for each displacement in attached file.

Displacement A: 2.50 km and 45° north of west

Ax= AcosФ = 2.50cos45° = 1.77 km (neg. direction)

Ay= AsenФ = 2.50sen45° = 1.77 km (pos. direction)

Displacement B: 4.70 km and 60° south of east

Bx= BcosФ = 4.70cos60° = 2,35 km (pos. direction)

By= BsenФ = 4.70sen60° = 4,07 km (neg. direction)

Displacement C: 1.30 km and 25° south of west

Cx= CcosФ = 1.30cos25° = 1,18 km (neg. direction)

Cy= CsenФ = 1.30sen25° = 0.55 km (neg. direction)

Displacement D: 5.10 km due east (0°)

Dx= DcosФ = 5.10 km (pos. direction)

Dy= DsenФ = 0 km

Displacement E: 1.70 km and 5° east of north

Ex= EsenФ = 1.70sen5° = 0,15 km (pos. direction)

Ey= EcosФ = 1.70cos5° = 1.69 km (pos. direction)

Displacement F: 7.20 km and 55° south of west

Fx= FcosФ = 7.20cos55° = 4.13 km (neg. direction)

Fy= FsenФ = 7.20sen55° = 5.90 km (neg. direction)

Displacement G: 2.80 km and 10° north of east

Gx= GcosФ = 2.80cos10° = 2.76 km (pos. direction)

Gy= GsenФ = 2.80sen10° = 0.49 km (pos. direction)

Now, we add the components along the x- and y- axis to find the components of the resultant (R):

Rx = Ax + Bx + Cx + Dx + Ex + Fx + Gx

Ry = Ay + By + Cy + Dy + Ey + Fy + Gy

Therefore,

Rx= (-1.77)+(2.35)+(-1.18)+(5.10)+(0.15)+(-4.13)+(2.76)

Ry= (1.77)+(-4.07)+(-0.55)+(0)+(1.69)+(-5.90)+(0.49)

Note: minus (-) symbol to negative directions

Rx = 3.28 km

Ry = - 6.57 km

Let´s use the Theorem of Pythagoras to find the magnitud ot the resultant:

$R = \sqrt{Rx^{2} +Ry^{2} }$

$R =\sqrt{(3.28)^{2}+(-6.57)^{2} }$

R = 7,34 km

To find the direction of the resultant:

tanФ = $\frac{Ry}{Rx}$

tanФ = $\frac{6.57}{3.28}$

tanФ = 2.00

Ф = tan-1 (2.00)

Ф = 63,43° north of east

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3 0

3 years ago

Which of the following sets of ordered pairs is a function?

sesenic [268]

Answer:

(1,5),(2,6),(4,5)

Step-by-step explanation:

Think of the answer choice in a table

x | y

1 | 5

2 | 6

4 | 5

exactly one input (x) has one output (y)

in a function likw this you have to make sure that the x is going to one y.

if not than it is not a function.

(1,2),(1,5)(3,9)

see the one in this orderd pair goes to 2 and 5 so in is not a function

6 0

3 years ago

A line passes through the points (-6, 4) and (-2, 2). Which is the equation of the line?

MissTica

Answer:

Step-by-step explanation:

7 0

3 years ago

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