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rewona [7]
3 years ago
11

Another personal question- are there any messaging sites that MIGHT work if most things are blocked via the school? I doubt anyt

hing will work but I don't exactly have much to lose so, if anyone is willing to help a poor teen out, please do so. Yes, im giving out brainliest to the one who helps the most.
Computers and Technology
2 answers:
noname [10]3 years ago
8 0

Answer:

sort of

Explanation:

all the sites that allow you to message other people, even bots ,are all blocked , if youre trying to talk to a friend try sharing a google doc

bezimeni [28]3 years ago
7 0

Well,

I searched it up and check how famous this would be.

1. Zoom - https://zoom.us/feature/messaging

2. SearchBug - https://www.searchbug.com/tools/free-text-messaging.aspx

3. SlyText - https://slytext.com/

I only sent this much because I don't want to have it deleted.

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Please list the computer data hierarchy from bit to database
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Answer:

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8 0
3 years ago
Write a program roman which converts numbers from decimal notation into Roman numerals. roman takes a single argument, a string
MaRussiya [10]

Answer:

// Program is written in C++ programming language

/ Comments are used for explanatory purpose

// Program starts here

#include<bits/stdc++.h>

using namespace std;

//Declare a function named value to represent the symbols of Roman Numerals

int value(char xy)

{

if (xy == 'I') { return 1; }

if (xy == 'V') { return 5; }

if (xy == 'X') { return 10; }

if (xy == 'L') { return 50; }

if (xy == 'C') { return 100; }

if (xy == 'D') { return 500; }

if (xy == 'M') { return 1000; }

return -1;

}

// Convert to numbers , taking Variable named input as input

int Converted(string &input)

{

// Declare a variable to store the calculated output

int calc;

// Set to 0

calc = 0;

// Iterate through input from 0 to the last character

for (int i=0; i<input.length(); i++)

{

int check1 = value(input[i]);

if (i+1 < input.length())

{

int check12= value(input[i+1]);

// Comparing both values

if (check1>= check2)

{

calc+ =check1;

}

else

{

calc+ =check2 - check1;

i++;

}

}

else

{

calc+ =check1;

}

}

return calc;

}

// Main method starts here

int main()

{

// String input declaration

string inp;

cout<"Enter any valid Roman numeral";

cout << "Result is "

<< Converted(inp);

return 0;

}

3 0
3 years ago
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