Answer:
c
Step-by-step explanation:
2-(-3)= 5
so the common difference is 5
<u>Question:</u>
Find the number of real number solutions for the equation. x^2 + 5x + 7 = 0
<u>Answer:</u>
The number of real solutions for the equation
is zero
<u>Solution:</u>
For a Quadratic Equation of form :
---- eqn 1
The solution is
Now , the given Quadratic Equation is
---- eqn 2
On comparing Equation (1) and Equation(2), we get
a = 1 , b = 5 and c = 7
In
,
is called the discriminant of the quadratic equation
Its value determines the nature of roots
Now, here are the rules with discriminants:
1) D > 0; there are 2 real solutions in the equation
2) D = 0; there is 1 real solution in the equation
3) D < 0; there are no real solutions in the equation
Now let solve for given equation

Since -3 is less than 0, this means that there are 0 real solutions in this equation.
O-O-T-O-T-T And I have calculated them
First do the the parenthesis: (6-3) = 3
Now you have [-4 + 3 * 8] -10
Next do multiplication: 3 *8 = 24
Now you have [-4 + 24]-10
Now do what is in brackets: -4 + 24 = 20
Now you have 20-10
Subtract 20-10 = 10
Answer:
y= -3/4x - 3
Step-by-step explanation:
-3/4 is the slope, so you replace m with the slope.
The y intercept is -3. If x is 4, and y is -6, we can plug that into an equation to find the y intercept. y=mx+b can change to -6= -3/4 * 4 + b. B = -3.