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3 years ago

Find the prime factorization of 120.

Mathematics

1 answer:

artcher [175]3 years ago

7 0

Answer:

(7/8 - 4/5)^2 = 9/

1600

= 0.005625

Step-by-step explanation:

Subtract: 7/

- 4/

= 7 · 5/

8 · 5

- 4 · 8/

5 · 8

= 35/

- 32/

= 35 - 32/

= 3/

For adding, subtracting, and comparing fractions, it is suitable to adjust both fractions to a common (equal, identical) denominator. The common denominator you can calculate as the least common multiple of both denominators - LCM(8, 5) = 40. In practice, it is enough to find the common denominator (not necessarily the lowest) by multiplying the denominators: 8 × 5 = 40. In the next intermediate step, the fraction result cannot be further simplified by canceling.

In words - seven eighths minus four-fifths = three fortieths.

Exponentiation: the result of step No. 1 ^ 2 = 3/

^ 2 = 32/

402

= 9/

1600

In words - three-fortieths squared = nine one-thousand six-hundredths.

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Write the equation for g(x).

MrRissso [65]

Answer:

g(x) = $5x^{2}$

Step-by-step explanation:

This problem may seem tricky at first, but after you understand the basic concepts about vertical stretches and vertical shrinks, this problem will become much simpler. Additionally, if you use the online tool: DESMOS, you will be able visualize things better.

First, you may notice the graph is more narrow than the original "f(x)" graph. This means that the g(x) graph is a vertical shrink. A vertical shrink can be achieved by adding a whole-number as a coefficient to the " $x^{2} \\$ " formula. Adding a coefficient of "5" would result in coordinates like (1,5), just like adding a coefficient of "2" for example would result in coordinates like (1,2).

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3 years ago

What do you get when you cross the Atlantic with the titanic

ANTONII [103]

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4 years ago

I forgot how to do this lol

astraxan [27]

The equation of the line has the form: y = ax+b parallel to the line y = -2x + 7
=> a= -2
Passes through (4,1) => x=4, y=1
Substituting into the equation:
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2 years ago

The dotplot below displays the difference in scores for 18 games between a high school soccer team and its opponent.

kiruha [24]

Answer: Choice D

In two games, the team lost to the opponent by 1 goal.

========================================================

Explanation:

Negative scores indicate the team lost, and the absolute value of those values represent how much of a loss.

So a difference of -1 means the team lost by 1 point.

We have 2 dots over this value, so there are 2 occasions where the team lost to the opponent by 1 goal.

An example would be that say the team scored 3 goals and the opponent scored 4 goals. So we have a differential of 3-4 = -1. The order is important because we would <u>not</u> say 4-3 = 1.

6 0

3 years ago

26. Students who take a statistics course are given a pre-test on the concepts and skills for the first chapter of a statistics

hjlf

The test statistic value lies to the right of the critical value. So we have sufficient evidence to reject the null hypothesis.

<h3>What are null hypotheses and alternative hypotheses?</h3>

In null hypotheses, there is no relationship between the two phenomenons under the assumption or it is not associated with the group. And in alternative hypotheses, there is a relationship between the two chosen unknowns.

Students who take a statistics course are given a pre-test on the concepts and skills for the first chapter of a statistics course.

Then they are given a post-test once the professor has concluded lecturing on the material.

Pre-test and post-test scores for 4 students in an elementary statistics class are given below.

Then we have

$\mu _d = \mu _{post} - \mu _{pre}$

Then the null hypotheses and alternative hypotheses will be

H₀: $\mu _d = 0$

Hₐ: $\mu _d > 0$

Then the test statistic will be

$\rm \overline{x} _d = \dfrac{\Sigma x_d}{n} = \dfrac{15+12+10+1}{4}\\\\\overline{x} _d = 9.5$

Then

$\rm S_d = 6.02$

The test statistic value is given by

$\rm t = \dfrac{\overline{x} _d }{\dfrac{S_d}{\sqrtn}} \\\\t = \dfrac{9.5}{\dfrac{6.02}{\sqrt4}}\\\\t = 3.16$

Since this is a right-tailed test, so the critical value is given by

$\rm t_{n-1}(\alpha ) = t_3 (0.05) = 2.353$

Since the test statistic value lies to the right of the critical value. So we have sufficient evidence to reject the null hypothesis.

Hence, we can conclude that $\mu _d > 0$ that is test scores have improved.

More about the null hypotheses and alternative hypotheses link is given below.

brainly.com/question/9504281

#SPJ1

7 0

2 years ago