Can someone please help me with this? I dont understand how to do these at all
1 answer:
The functions are:
i)
ii)
.
We note that both Sin and Cos functions cannot produces values smaller than -1, or larger than 1.
In other words, the range of both these functions is [-1, 1].
Whatever expression A is, sin(A) and cos(A) are values in [-1, 1].
Assume
produced its maximal value, 1, then 
makes this value 3.
Thus, the maximum value of g(x) is 3, as can be also seen in the graph.
Similarly, assume cos(x) produced 1, then 2cos(x) makes it 2. Thus, the greatest value of f(x) is 2.
Answer: max{f(x)}=2, max{g(x)}=3, so g has the largest maximal value.
i)
ii)
We note that both Sin and Cos functions cannot produces values smaller than -1, or larger than 1.
In other words, the range of both these functions is [-1, 1].
Whatever expression A is, sin(A) and cos(A) are values in [-1, 1].
Assume
Thus, the maximum value of g(x) is 3, as can be also seen in the graph.
Similarly, assume cos(x) produced 1, then 2cos(x) makes it 2. Thus, the greatest value of f(x) is 2.
Answer: max{f(x)}=2, max{g(x)}=3, so g has the largest maximal value.
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Answer:
The experimental probability that a light build chosen at random has no defects is 99.5 % or P(A)=0.995.
Step-by-step explanation:
let S be the sample space for the inspection of the light bulbs.
Therefore, n(s) = 800
let ' A ' be the event of no defects bulbs.
Therefore, n(A) = 796
Now the Experiment probability for a light bulb chosen has no defects will be given by,
Substituting the values we get
The experimental probability that a light build chosen at random has no defects is 99.5 % or P(A)=0.995.