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3 years ago

How many inches is 10 1/2 feet?

Mathematics

2 answers:

dexar [7]3 years ago

3 0

Your answer is 126 inches. You take 10.5 times 12 because there is 12 inches in a foot.

storchak [24]3 years ago

3 0

126 inches

10.5 x 12 = 126 inches

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What are the factors of 66

Elena-2011 [213]

1 x 66

2 x 33

3 x 22

6 x 11

That's all the factors

7 0

2 years ago

PLEASE HELP ME!!!!!.........

DedPeter [7]

Answer:

Step-by-step explanation:

Trust me.

5 0

2 years ago

José plotted points on a coordinate plane to represent the vertices of a rectangle. The first

Tema [17]

Jose's rectangle must have equal and parallel opposite sides

The coordinates of the other points could be C(7,5) and D(7,1)

<h3>How to determine the other points?</h3>

The coordinates are given as;

A = (2,5).

B = (2,1).

To form a rectangle, each of the remaining points must have the same y-coordinates as points A and B.

So, we have:

C = (x,5)

D = (x,1)

Also, the remaining points must have the same x-coordinates.

i.e.

Cx = Dx

From the list of options, we have:

C(7,5) and D(7,1)

Hence, the coordinates of the other points could be C(7,5) and D(7,1)

Read more about rectangles at:

brainly.com/question/12500692

3 0

2 years ago

Is -8.3 a rational number? if so can you provide it in a/b form

zalisa [80]

Answer:

yes $-8.3=\frac{-83}{10}\\is ~of ~the ~form ~\frac{a}{b} ~where ~a=-83, ~b=10$

Step-by-step explanation:

6 0

2 years ago

Find S^20 if the series 1 + 1.1 ..... is a (a) arithmetic (b) geometric

quester [9]

I'm guessing S^20 is actually referring to the 20th partial sum $S_{20}$ , with

$S_{20}=1+(1+1\times0.1)+(1+2\times0.1)+\cdots+(1+18\times0.1)+(1+19\times0.1)$

in the arithmetic case, and

$S_{20}=1+1.1+1.1^2+\cdots+1.1^{18}+1.1^{19}$

in the geometric case.

(a) Combining like terms, we have

$S_{20}=20+0.1(1+2+\cdots+18+19)$

and invoking the formula

$1+2+\cdots+(n-1)+n=\dfrac{n(n+1)}2$

we end up with

$S_{20}=20+0.1\dfrac{19\times20}2=39$

(b) Multiply $S_{20}$ by 1.1, then subtract this from $S_{20}$ :

$1.1S_{20}=1.1+1.1^2+1.1^3+\cdots+1.1^{19}+1.1^{20}$

$S_{20}-1.1S_{20}=-0.1S_{20}=1-1.1^{20}$
$\implies S_{20}=\dfrac{1.1^{20}-1}{0.1}\approx57.275$

7 0

3 years ago