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3 years ago

Which of the following values are solutions to the inequality 3x+10\ge 2?3x+10≥2?

Mathematics

1 answer:

FromTheMoon [43]3 years ago

7 0

9514 1404 393

Answer:

I and II

Step-by-step explanation:

The inequality ...

3x +10 ≥ 2

has solutions ...

3x ≥ -8 . . . . . . . . subtract10

x ≥ -2 2/3 . . . . . divide by 3

Of the answer choices {-1, 3, -11}, the ones that are greater than -2 2/3 are ...

-1, 3 . . . . . . I and II only

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Answer: Step 1: Reverse the signs of $6x^3-2x + 3$ expression.

Step 2: Removing parenthesis

Step 3: Grouping like terms

Step 4: Combing like terms

Step 5: Writing the final expression in standard form

Step-by-step explanation: First expression : $6x^3-2x + 3$

Second expression : $-3x^3+5x^2+4x-7$ .

We need to subtract $6x^3-2x + 3$ from $-3x^3+5x^2+4x-7$ .

Step 1: Reverse the signs of $6x^3-2x + 3$ expression.

$(-3x^3+5x^2+4x-7)+(-6x3+2x-3)$

Step 2: Removing parenthesis

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Step 3: Grouping like terms

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Step 4: Combing like terms

$-9x^3 + 6x + (-10) + 5x^2$

Step 5: Writing the final expression in standard form

$-9x^3 + 5x^2 + 6x-10$

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Step-by-step explanation:

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Answer:

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Step-by-step explanation:

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146,273,011

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Step 1: Round

146,273,011

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