Answer:
20. ![x\left(x-6\right)\left(x+8\right)](https://tex.z-dn.net/?f=x%5Cleft%28x-6%5Cright%29%5Cleft%28x%2B8%5Cright%29)
22. ![2\left(x+1\right)\left(x+4\right)](https://tex.z-dn.net/?f=2%5Cleft%28x%2B1%5Cright%29%5Cleft%28x%2B4%5Cright%29)
24. ![5m\left(m-1\right)\left(m+7\right)](https://tex.z-dn.net/?f=5m%5Cleft%28m-1%5Cright%29%5Cleft%28m%2B7%5Cright%29)
Step-by-step explanation:
20. ![x^3+2x^{2} -48x](https://tex.z-dn.net/?f=x%5E3%2B2x%5E%7B2%7D%20-48x)
The GCF is x, so you group it out of the equation first.
![x(x^{2} +2x-48)](https://tex.z-dn.net/?f=x%28x%5E%7B2%7D%20%2B2x-48%29)
Then, you find 2 numbers that will equal to 2 when you add them and will equal to -48 when you multiply them.
![?+?=2\\?*?=-48](https://tex.z-dn.net/?f=%3F%2B%3F%3D2%5C%5C%3F%2A%3F%3D-48)
The two numbers would be -6 and 8. You then differentiate the squares.
![x\left(x-6\right)\left(x+8\right)](https://tex.z-dn.net/?f=x%5Cleft%28x-6%5Cright%29%5Cleft%28x%2B8%5Cright%29)
22. ![2x^{2} +10x+8](https://tex.z-dn.net/?f=2x%5E%7B2%7D%20%2B10x%2B8)
The GCF is 2, so you must group it out.
![2(x^{2} +5x+4)](https://tex.z-dn.net/?f=2%28x%5E%7B2%7D%20%2B5x%2B4%29)
Find the two numbers that will equal to 5 when you add them and will equal to 4 when you multiply them.
![?+?=5\\?*?=4](https://tex.z-dn.net/?f=%3F%2B%3F%3D5%5C%5C%3F%2A%3F%3D4)
The two numbers would be 1 and 4. Finally, differentiate the squares.
![2\left(x+1\right)\left(x+4\right)](https://tex.z-dn.net/?f=2%5Cleft%28x%2B1%5Cright%29%5Cleft%28x%2B4%5Cright%29)
24. ![5m^{3} +30m^2-35m](https://tex.z-dn.net/?f=5m%5E%7B3%7D%20%2B30m%5E2-35m)
The GCF is 5m, so you must group it out.
![5m(m^2+6m-7)](https://tex.z-dn.net/?f=5m%28m%5E2%2B6m-7%29)
Find the two numbers that will equal to 6 when you add them and will equal to -7 when you multiply them.
![?+?=6\\?*?=-7](https://tex.z-dn.net/?f=%3F%2B%3F%3D6%5C%5C%3F%2A%3F%3D-7)
The two numbers would be -1 and 7. Finally, differentiate the squares.
![5m\left(m-1\right)\left(m+7\right)](https://tex.z-dn.net/?f=5m%5Cleft%28m-1%5Cright%29%5Cleft%28m%2B7%5Cright%29)
Answer:
192y16
Step-by-step explanation:
mark me brainlist
There are many examples to pick from, but one example is this:
The set of rational numbers (aka any fraction of two integers) is closed under the operation of division. Divide any two rational numbers and we get some other rational number.
However, the set of integers is not closed under division. If we divided 10 over 3, then we get 10/3 = 3.333 approximately which isn't an integer. So just because the set of integers is a subset of the rationals, it doesn't mean that the idea of closure follows suit from superset to subset.
Side note: The term "superset" is basically the reverse of a subset. If A is a subset of B, then B is a superset of A.
Answer:
$7.50
Step-by-step explanation:
Madison is planning to get some apples for her homemade pie. At the grocery store there is a display showing 5 apples for $12.50. How much money would it be if Madison wanted 3 apples?
Answer:
x=-1 2/5
Step-by-step explanation:
3(x-6)-8x=-2+5(2x+1)
3x-18-8x=-2+10x+5
-18-5x=10x+3
15x=-21
x=-7/5
x=-1 2/5
plz mark brainliest