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Allisa [31]
4 years ago
13

Write and evaluate the expression. Then, complete the statement.

Mathematics
2 answers:
jeka944 years ago
8 0

Answer:

12

Step-by-step explanation:

vlabodo [156]4 years ago
6 0

Answer:

i have that same question and no ones answered yet.

Step-by-step explanation:

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Hi, what’s your question?
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Which one of these rule cannot be used for the congruent triangles?
erastovalidia [21]
Answered : 4.SSA hope this helps
7 0
3 years ago
Which equation represents a circle with a center at (-3,-5) and a radius of 6 units?
brilliants [131]

Answer:

Step-by-step explanation:

The equation of a circle is:

(x - h)² + (y - k)² = r²

where (h, k) is the center and r is the radius.

Given that (h, k) is (-3, -5) and r = 6:

(x + 3)² + (y + 5)² = 6²

(x + 3)² + (y + 5)² = 36

7 0
3 years ago
Read 2 more answers
Mr. Smith invests a certain amount of money at 8% and twice as much at 5%. If his annual income from the two investments is $720
professor190 [17]

The amount invested by Mr.Smith in 5% is $240 .

<u>Step-by-step explanation:</u>

We have , Mr. Smith invests a certain amount of money at 8% and twice as much at 5%. If his annual income from the two investments is $720 . Let us suppose that Mr.Smith invest $x so :

Amount of money invested in 5% is \frac{5x}{100} . And, amount of money invested in 8% is twice that of 5% i.e. \frac{(2)5x}{100} = \frac{10x}{100} .

Now, total investment is $720 so,

\frac{5x}{100} +( \frac{(2)5x}{100} = \frac{10x}{100} ) = $720

⇒ \frac{5x}{100}  + \frac{10x}{100}  = 720

⇒ \frac{15x}{100}    = 720

⇒ \frac{100(720)}{15}    = x

⇒ x = 4800

The amount invested by Mr.Smith in 5% is \frac{5x}{100} i.e.\frac{5(4800)}{100} = 240. ∴ The amount invested by Mr.Smith in 5% is $240 .

8 0
3 years ago
Suppose that scores on the mathematics part of a test for eighth-grade students follow a Normal distribution with standard devia
riadik2000 [5.3K]

Answer:

We need an SRS of scores of at least 153.

Step-by-step explanation:

We have that to find our \alpha level, that is the subtraction of 1 by the confidence interval divided by 2. So:

\alpha = \frac{1-0.9}{2} = 0.05

Now, we have to find z in the Ztable as such z has a pvalue of 1-\alpha.

So it is z with a pvalue of 1-0.05 = 0.95, so z = 1.645

Now, find M as such

M = z*\frac{\sigma}{\sqrt{n}}

In which \sigma is the standard deviation of the population and n is the size of the sample.

How large an SRS of scores must you choose?

This is at least n, in which n is found when M = 20, \sigma = 150. So

M = z*\frac{\sigma}{\sqrt{n}}

20 = 1.645*\frac{150}{\sqrt{n}}

20\sqrt{n} = 1.645*150

\sqrt{n} = \frac{1.645*150}{20}

\sqrt{n} = 12.3375

(\sqrt{n})^{2} = (12.3375)^{2}

n = 152.2

Rounding to the next whole number, 153

We need an SRS of scores of at least 153.

8 0
3 years ago
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