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fiasKO [112]
3 years ago
6

Which equation represents a circle with a center at (-3,-5) and a radius of 6 units?

Mathematics
2 answers:
brilliants [131]3 years ago
7 0

Answer:

Step-by-step explanation:

The equation of a circle is:

(x - h)² + (y - k)² = r²

where (h, k) is the center and r is the radius.

Given that (h, k) is (-3, -5) and r = 6:

(x + 3)² + (y + 5)² = 6²

(x + 3)² + (y + 5)² = 36

Tema [17]3 years ago
3 0

Answer:

(x+3)^2+(y+5)^2=36

Step-by-step explanation:

edgenuity 2020

hope this helps!

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F(x) 2 square root -x^2+10 x what’s the domain
SSSSS [86.1K]

The domain of the function are all real numbers greater than 10

<h3>Domain of a function</h3>

Domain are values of the independent variables for which the function exist.

Given the function below;

f(x)=2\sqrt{-x^2+10x}

For the function to exist, then;

-x^2+10x = 0

-x^2 = -10x

x = 10

Hence the domain of the function are all real numbers greater than 10

Learn more on domain here: brainly.com/question/26098895

#SPJ1

4 0
2 years ago
Use the upper and lower sums to approximate the area of the region using the given number of subintervals (of equal width)
Mashutka [201]
From the figure shown, the interval is divided into 5 equal parts making each subinterval to be 0.2.

Part A:

y= \sqrt{1-x^2}

The approximate the area of the region shown in the figure using the lower sums is given by:

 Area= [y(0.2)\times0.2]+[y(0.4)\times0.2]+[y(0.6)\times0.2]+[y(0.8)\times0.2] \\ +[y(1)\times0.2] \\  \\ =[\sqrt{1-(0.2)^2}\times0.2]+[\sqrt{1-(0.4)^2}\times0.2]+[\sqrt{1-(0.6)^2}\times0.2] \\ +[\sqrt{1-(0.8)^2}\times0.2]+[\sqrt{1-(1)^2}\times0.2] \\  \\ =(0.9798\times0.2)+(0.9165\times0.2)+(0.8\times0.2)+(0.6\times0.2)+(0\times0.2) \\  \\ =0.196+0.183+0.16+0.12=0.659



Part B:

The approximate the area of the region shown in the figure using the lower sums is given by:

 Area= [y(0)\times0.2]+[y(0.2)\times0.2]+[y(0.4)\times0.2]+[y(0.6)\times0.2] \\ +[y(0.8)\times0.2] \\ \\ =[\sqrt{1-(0)^2}\times0.2]+[\sqrt{1-(0.2)^2}\times0.2]+[\sqrt{1-(0.4)^2}\times0.2] \\ +[\sqrt{1-(0.6)^2}\times0.2] +[\sqrt{1-(0.8)^2}\times0.2] \\ \\ =(1\times0.2)+(0.9798\times0.2)+(0.9165\times0.2)+(0.8\times0.2)+(0.6\times0.2) \\ \\ =0.2+0.196+0.183+0.16+0.12=0.859



Part C:

The approximate area of the given region is given by

Area= \frac{0.659+0.859}{2} = \frac{1.518}{2} =0.759
7 0
4 years ago
Given the equation y=2x-8, which statement is correct ? A.Y=2(x-4) has a y-intercept of 4 B. Y=2(x-4)has a y-intercept of -4 C.
kakasveta [241]

Answer:

Correct option: C -> Y=2(x-4) has a x- intercept of 4

Step-by-step explanation:

To find the y-intercept of the equation y = 2x - 8, we just need to find the value of y when x = 0:

y = 2*0 - 8 = -8

To find the x-intercept of the equation y = 2x - 8, we just need to find the value of x when y = 0:

0 = 2*x - 8

2x = 8

x = 4

So the y-intercept is -8 and the x-intercept is 4.

Correct option: C -> Y=2(x-4) has a x- intercept of 4

3 0
3 years ago
Whats the answer to this question?
forsale [732]

Answer:

0.67%

Step-by-step explanation:

2/300

3 0
3 years ago
Read 2 more answers
Please help! I'll give out the brainiest!
gavmur [86]
To find the solution
-4x>36
divide both sides by -4
(REMEMBER WHEN YOU DIVIDE BY A NEGATIVE, THE SIGN FLIPS OVER)
x < -36/4
simplified
x < -9

Hope this helps :)
6 0
3 years ago
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