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barxatty [35]
3 years ago
13

8th Grade Functions: Bike Race

Mathematics
2 answers:
Svetach [21]3 years ago
7 0

Answer: 12

Step-by-step explanation:

Arturiano [62]3 years ago
5 0

Answer:

Juan wins the race

Step-by-step explanation:

<u>The graph is shown in attached image.</u>

<u />

The black line is Juan's graph.

The green line is Antonio's graph.

The graph shows the distance (y-axis) with time (x-axis).

The end of the curve(s) means the end of the race. Both curve's ending point in y-axis is 4 miles so the end of the race is 4 miles.

But in x-axis, we see the time:

Juan finishes at 13 minutes

Antonio finishes at 15 minutes

<u>Definitely Juan wins the race</u>

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(A)Segment EF, segment FG, segment GH, and segment EH are congruent

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<u>Step 1</u>

Quadrilateral EFGH with points E(-2,3), F(1,6), G(4,3), H(1,0)

<u>Step 2</u>

Using the distance formula

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Given G(4,3), H(1,0)

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|EH|=\sqrt{(0-3)^2+(1-(-2))^2}=\sqrt{(-3)^2+(3)^2}=\sqrt{18}=3\sqrt{2}

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Segment EF ,E (−2, 3), F (1, 6)

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Segment GH, G (4, 3), H (1, 0)

Slope of |GH|= \frac{0-3}{1-4} =\frac{-3}{-3}=1

<u>Step 4</u>

Segment EH, E(−2, 3), H (1, 0)

Slope of |EH|= \frac{0-3}{1+2} =\frac{-3}{3}=-1

Segment FG, F (1, 6,) G (4, 3)

Slope of |EH| =\frac{3-6}{4-1} =\frac{-3}{3}=-1

<u>Step 5</u>

Segment EF and segment GH are perpendicular to segment FG.

The slope of segment EF and segment GH is 1. The slope of segment FG is −1.

<u>Step 6</u>

<u>Segment EF, segment FG, segment GH, and segment EH are congruent. </u>

The slope of segment FG and segment EH is −1. The slope of segment GH is 1.

<u>Step 7</u>

All sides are congruent, opposite sides are parallel, and adjacent sides are perpendicular. Quadrilateral EFGH is a square

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