Answer:
D(1, 2) → D'(2, 7)
E(-3, -5) → E'(-10, 0)
F(4, -1) → F'(11, 4)
Step-by-step explanation:
D(1, 2) → D' ________
Translate image (3x - 1, y + 5)
(1, 2), x = 1 and y = 2
3x - 1 = 3(1) - 1 = 3 - 1 = 2
y + 5 = (2) + 5 = 7
E(-3, -5) → E' ________
(-3, -5), x = -3 and y = -5
3x - 1 = 3(-3) - 1 = -9 - 1 = -10
y + 5 = (-5) + 5 = 0
F(4, -1) → F' ________
(4, -1), x = 4 and y = -1
3x - 1 = 3(4) - 1 = 12 - 1 = 11
y + 5 = (-1) + 5 = 4
So if one bit of the length, is half the size of the other bit then we can make the following equation, for x being the length of rope:
x + 2x = 66
3x = 66
x = 22
That is the length, of the smaller one (half the big one), so 2x = 44. Hence d) is your answer.
Hope I helped!
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Step-by-step explanation:
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