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Zigmanuir [339]
3 years ago
6

What are the coordinates of point A?

Mathematics
1 answer:
Virty [35]3 years ago
3 0
(-4,-3) need 20 characters
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4
erik [133]

Answer:

47

Step-by-step explanation:

the lines are parrele which explains

why its 47

7 0
3 years ago
Is 69 square routed a even number
STatiana [176]
No it is not, the square root is 8.3
6 0
3 years ago
the line whose equation is y=1/2x-3 is dilated by a factor of 3 with a center at the point (10,2). Explain why its equation woul
lana [24]
We  have that

<span>y=1/2x-3
1) the slope of this line equation is m=(1/2)
2) the coordinates of the y intercept are
for x=0
y=-3
point (0,-3)
3)</span>the coordinates of the x intercept are
for y=0
0=(1/2)x-3------> (1/2)x=3----> x=6
point (6,0)

<span>if the line is dilated by a factor of 3
then
</span>y=1/2x-3--------> 3y=3*[1/2x-3]-----> 3y=(3/2)x-9
3y=(3x-18)/2-------> y=(3x-18)/6--------> y=(3/6)x-18/6

 y=(3/6)x-18/6
so
1) the slope of this line equation is m=(3/6)-----> 3/6=1/2
2) the coordinates of the y intercept are
for x=0
y=-18/6-------> y=-3
point (0,-3)
3)the coordinates of the x intercept are
for y=0
0=(3/6)x-18/6------> (3/6)x=18/6----> x=18/3------> x=6
point (6,0)

therefore
the equation of the line
y=1/2x-3 is the same that the equation of the line  y=(3/6)x-18/6

<span>the equation does not change because the slope and the x and y intercepts do not change either</span>
6 0
3 years ago
A person on the ground looks up at an angle of 28° and sees the top of a tree and the top of a building aligned. The tree is 20
lorasvet [3.4K]

Answer:

21.27 meters.

Step-by-step explanation:

Please find the attachment.

Let H and h represent height of building and tree respectively.

We have been given that a person on the ground looks up at an angle of 28° and sees the top of a tree and the top of a building aligned. The tree is 20 m away from the person and the building is 60 m away from the person.

We know that tangent relates opposite side of a right triangle with its adjacent side.

\text{tan}=\frac{\text{Opposite}}{\text{Adjacent}}

\text{tan}(28^{\circ})=\frac{H}{60}

60\cdot \text{tan}(28^{\circ})=H

60\cdot 0.531709431661=H

H=31.90256589966\approx 31.90

Similarly, we can find height of the tree.

\text{tan}(28^{\circ})=\frac{h}{20}

20\cdot\text{tan}(28^{\circ})=h

20\cdot 0.531709431661=h

h=10.63418863322\approx 10.63

H-h=31.90-10.63

H-h=21.27

Therefore, the difference in heights between the building and tree is 21.27 meters.

3 0
3 years ago
Help on this question
mars1129 [50]
The answer to ur problem is -5.20
6 0
3 years ago
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