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noname [10]
4 years ago
10

How many two-person committees can be formed from a group of six people,

Mathematics
1 answer:
finlep [7]4 years ago
8 0

Answer:

3 two-person committee's can be formed from a group of six people

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Explain why 6^3x7^3=42^3 is correct.
Orlov [11]

Answer:

{6}^{3} \times {7}^{3}  =  {(6 \times 7)}^{3}  =  {42}^{3}

Step-by-step explanation:

When two or more quantities have the same exponents, their bases can be multiplied together.

4 0
3 years ago
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A city-wide gardening club is up of men, women and children in the ratio 5:4:11.
Sever21 [200]

Answer:

Women: 448  Men: 560  Children: 1232

Step-by-step explanation:

5+4+11 = 20/2240 = 112

Women = 4 x 112 = 448

Men = 5 x 112 = 560

Children = 11 x 112 = 1232

Total = 1232 + 560 +448 = 2240

3 0
3 years ago
Solve the following equation: lim x->0 sin3x/5x^3-4x.
goblinko [34]
Usual limit of sin is sinX/X--->1, when X--->0

sin3x/5x^3-4x=0/0?, sin3x/3x--->1 when x --->0, so sin3x/5x^3-4x=                    [3x. sin3x / 3x] /(5x^3-4x)=(sin3x / 3x) . (3x/5x^3-4x)
   =(sin3x / 3x) . (3/5x^2- 4)
finally lim  sin3x/5x^3-4x=lim (sin3x / 3x) .(3/5x^2- 4)=1x(3/-4)= - 3/4
                 x----->0            x---->0
3 0
3 years ago
Suppose you pick two cards from a deck of 52 playing cards. What is the probability that they are both queens?
photoshop1234 [79]

Answer:

0.45% probability that they are both queens.

Step-by-step explanation:

A probability is the number of desired outcomes divided by the number of total outcomes

The combinations formula is important in this problem:

C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

Desired outcomes

You want 2 queens. Four cards are queens. I am going to call then A,B,C,D. A and B is the same outcome as B and A. That is, the order is not important, so this is why we use the combinations formula.

The number of desired outcomes is a combinations of 2 cards from a set of 4(queens). So

D = C_{4,2} = \frac{4!}{2!(4-2)!} = 6

Total outcomes

Combinations of 2 from a set of 52(number of playing cards). So

T = C_{52,2} = \frac{52!}{2!(52-2)!} = 1326

What is the probability that they are both queens?

P = \frac{D}{T} = \frac{6}{1326} = 0.0045

0.45% probability that they are both queens.

4 0
3 years ago
A square classroom has sides that are 21 feet long. what is the room's perimeter
lutik1710 [3]
The answer is 84 because 21 times 4 equals 84
4 0
3 years ago
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