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Alona [7]
3 years ago
12

Which is the equation of a line that passes through (1,8) and (6,4)

Mathematics
1 answer:
Sati [7]3 years ago
8 0

Answer:

<em>y = - </em>\frac{4}{5}<em> x + </em>\frac{44}{5}<em> </em>

Step-by-step explanation:

(6, 4)

(1, 8)

m = \frac{8-4}{1-6} = - \frac{4}{5}

y - 4 = - \frac{4}{5} ( x - 6 )

<em>y = - </em>\frac{4}{5}<em> x + </em>\frac{44}{5} ⇔ y = - 0.8x + 8.8

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How many sides do 1980 have
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Answer:

13 sides

Step-by-step explanation:

1980 = (n − 2)×180         Formula for number of sides

n − 2 = 1980/180            Divide both sides by 180

n - 2 = 11            

  + 2   + 2                       Add 2 to both sides

n = 13

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In the figure, a∥b and m∠1 = 34°.<br><br> What is the m∠5 ?
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Assuming line J is parallel to k.

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3 0
3 years ago
The numerals represent cardinalities in the Venn diagram,3$6B(a) Find the cardinality of the set AB(b) Find the cardinality of t
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a) A∩B this symbol means the intersection between A and B, in the Venn diagram, is represented by the crossing between the two circles.

According to the diagram there are 9 cardinalities shared by both circles so

A∩B= 9

b) A∪B is the union between both events, it means that you are looking for the cardinalities that are included in A or B but not both, symbolically this is:

A∪B= A + B - A∩B

The total cardinalities included in A are 5 + 9= 14

The total cardinalities included in B are 6 + 9= 15

Note that the elements in the intersection are included in both circles, meaning that they will be counted twice, this is why you have to subtract it.

A∪B= A + B - A∩B= 14 + 15 - 9= 20

c) A∩B'

B' is the complement of B, this means that it includes all elements of U that are not included in B.

If U= 23 and B= 15 then B'= U - B= 23-15= 8

The cardinalities included in A∩B'=5

d) A'∩B

A' is the complement of A and includes all cardinalities that are outside that circle.

To know how many those are you have to do the same calculation as you did in the item before:

A'= U-A= 23-14= 9

From those 9 cardinalities only 6 are shared by both A' and B so,

A'∩B=6

e) A'∩B'

A'= 9

B'= 8

A'∩B'= 9+8= 17

7 0
1 year ago
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