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egoroff_w [7]
3 years ago
6

Train A leaves Westtown and travels at 50 mph toward Smithville, 330 miles away. At the same time, Train B leaves Smithville and

travels at 60 mph toward Westtown. After how many hours do the two trains meet? Enter your answer in the box.

Mathematics
2 answers:
Hoochie [10]3 years ago
8 0
Here is your answer....

malfutka [58]3 years ago
8 0

Answer: Hello mate!

first, let's do a list with all the things we know about this problem:

Both trains depart at the same time; we can define this time as t = 0 in hours.

the velocity of train A is 50mph

the velocity of train B is 60mph

both trains travel in opposite directions.

the initial distance between both trains is equal to 330 miles:

we want to know when the trains will meet each other:

The trains will meet each other when the sum of their traveled distance is equal to the initial separation between them.

the distance traveled by the train A is equal to his velocity multiplied by the time that passed since it departed.

this is: Da(t) = (50*t)mi

and the distance for the train B is: Db(t) = (60*t)mi

then, as we know, the trains will meet when Da(t) + Db(t) = 330mi

then 50*t + 60*t = 330

110*t = 330

t = 330/110 = 3h

the trains will meet 3 hours after they departed.

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yawa3891 [41]
Degrees: s = \frac{\pi}{180}\theta r
                s = \frac{\pi}{180}(\frac{s}{r})(r)
                <span>s = \frac{\pi}{180}(\frac{165}{4})(4)
                </span>s = \frac{\pi}{180}(41.25)(4)
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                s = \frac{165\pi}{180}
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                s = 11 * 15
                s = 165\°

Radians: s = \theta r
               s = \frac{s}{r}(r)
               s = \frac{165}{4}(4)
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8 0
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