Please use the solution below:
Let P = perimeter, A = area
As provided above, a = xy and
We know that the formula to solve for the perimeter of a rectangle is P = 2x + 2y. Using the given 112m, we can solve the perimeter using the formula:
112 = 2x + 2y
56 = x + y
x = 56-y or y = 56-x
Let's solve the perimeter in terms of y using the formula below:
A = (56-y)(y)
Find the derivative of A = 56-y^2 to get the value of y.
dA/dy = 56-2y = 0
y = 56/2
y = 28
To find X, substitute the value of y in the equation x = 56 - y.
x = 56 - 28
Therefore, x = 28.
We can conclude that the figure is not a rectangle but a square.
Answer:
the system has a unique solution
Step-by-step explanation:
Start with an equation of a line in standard form,
Solve it for y to put it into the slope-intercept form:
The slope is -a/b.
Now look at your system of equations. The slope of the first equation is -a/b = -2/3. The slope of the second equation is -a/b = -6/5.
You have a system of two linear equations with two lines with different slopes, so the lines must intersect at a single point.
Answer: the system has a unique solution
Answer:
ok
Step-by-step explanation:
ANSWER
w=48,l=60
EXPLANATION
Let the width of the field be, w , then,
the length of the field will be:
The area of a rectangle is
This implies that:
Expand
This implies that,
The dimensions are positive, the width is 48 and the length is 12+48=60
Answer: 8) 42°, 65°, 115° 9) 1.5, 2
Step-by-step explanation:
8) Right off the bat I know that the measure adjacent to 157° is
23°. With both numbers inside the triangle combined, we get
65° meaning the last number is 115 because that'll add up to 180°
9) Considering the smaller triangle has half the length of the bigger triangle
The length of the rest are half the size too.
EF = 1.5
DF = 2
