To compute the distance between the points, we can apply the distance formula as shown below.

In which x₁ and x₂ are the x-coordinates and y₁ and y₂ are the y-coordinates of the two points. Thus, applying this with the segments AABB, AACC, and BBCC, we have



Now that we have the lengths of all the sides of ΔAABBCC, we can find the missing angles using the Law of Cosines.
Generally, we have

or

Hence, we have



Simplifying this, we have


Thus, from this, we can arrange the angles from smallest to largest: ∠CC, ∠AA, and ∠BB.
Answer: ∠CC, ∠AA, and ∠BB
Answer:
The volume is 210 cm³
Step-by-step explanation:
The way to solve volume is LxWxH, so you would do 6x5x7 and you get 210.
Answer:
P(P, then Y)=(1/11)(1/10)=1/110
Step-by-step explanation:
The number of letters in probability is 11.
There is 1 P.
The probability of drawing a P on draw 1 is the number of ways of drawing a P, which is 1, divided by the number of ways of drawing any letter, which is 11. Thus:
Probability of drawing a P on the first draw is 1/11.
There are now 10 letters left. There is 1 Y. so
Probability of drawing a Y on the second draw given that you drew a P on the first draw is 1/10.
The probability of drawing a P on the first draw and a Y on the second draw is
(probability of a P on draw 1)(probability of drawing a Y on draw 2, given a P on draw 1)
P(P, then Y)=(1/11)(1/10)=1/110
Answer:
y = x + 8
Step-by-step explanation:
For 8cm of thread, 1cm of the bracelet may be produced. therefore being y(thread) = x(bracelet) with the addition of 8 (+8). Hope this helps!
54 I'm pretty sure, sorry if I'm wrong