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3 years ago

How to tell if a system of equations has no solution or infinitely many?

Mathematics

1 answer:

Alenkasestr [34]3 years ago

5 0

Non of the lines are the same, the equations are dependent linear equations.

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2x+4y=6<br> 3x=12-6y<br> Solve by elimination

faltersainse [42]

Answer:

no solution

Step-by-step explanation:

2x + 4y = 6......reduces to x + 2y = 3

3x = 12 - 6y....reduces to x = 4 - 2y...rearranged is x + 2y = 4

so now we have :

x + 2y = 3

x + 2y = 4

ok....I dont have to go any farther to know that this has no solution because ur equations have the same slope and different y int, this means ur lines are parallel and have no solution because they never cross each others path.

5 0

3 years ago

Read 2 more answers

What is the distance between (–4, –10) and (–4, –4)?

Gre4nikov [31]

Answer:

6 units

Step-by-step explanation:

(-4 , -10) ; (-4 , -4)

Distance = $\sqrt{(x_{2}-x_{1})^{2}+(y_{2}-y_{1})^{2}}$

$= \sqrt{(-4-[-4])^{2}+(-4-[-10])^{2}}\\\\= \sqrt{(-4+4)^{2}+(-4+10)^{2}}\\\\=\sqrt{0+(6)^{2}}\\\\= \sqrt{36}\\\\= 6$

4 0

2 years ago

Read 2 more answers

Assume all variables represent non negative numbers . Help please!!

Dafna1 [17]

Answer:

A). $2p^{8}$

B). $3m^{7}$

Step-by-step explanation:

A). $\sqrt{4p^{16}}$

To get the square root of the given expression we will convert it into the square form.

$4p^{16}=(2)^2(p^{8})^2$ [Since 2×2 = 4 and $p^{8}\times p^{8}=p^{16}$ ]

Therefore, $\sqrt{4p^{16}}=\sqrt{2^{2}\times (p^{8})^2 }$

$=2p^{8}$

B). $\sqrt{9m^{44}}$

Since, $9m^{14}=(3)^2\times (m^7)^2$

Therefore, $\sqrt{9m^{44}}=\sqrt{(3)^2\times (m^7)^2}$ [Since 3² = 9 and (m⁷)² = m¹⁴]

$=3m^{7}$

7 0

3 years ago

I need help I’m stuck on this

arsen [322]

press ask for help i think it my help im also stumped on that

8 0

2 years ago

Find lcm and hcf of 168 and 126

Nuetrik [128]

Answer:

LCM is 504. GCF is 42

Step-by-step explanation:

6 0

2 years ago