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yanalaym [24]
4 years ago
14

Solve two step inequalities

Mathematics
1 answer:
UkoKoshka [18]4 years ago
4 0
4 x < 24

x < 6

x/13 + 3 >= 4

x/13 >= 1

x >= 13

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How do I solve 1/2 in minus 3 equals 5 ​
Mandarinka [93]

Answer:

  n = 16

Step-by-step explanation:

\dfrac{1}{2}n-3=5\\\\\dfrac{1}{2}n=8 \qquad\text{add 3}\\\\n=16 \qquad\text{multiply by 2}

___

In general, you identify the terms containing the variable. Then figure out what is being done to the variable. Here, it is multiplied by 1/2 and then 3 is subtracted. You undo these operations in reverse order.

Undo the subtraction of 3 by adding 3. Undo the multiplication by 1/2 by multiplying by its inverse, 2. Of course, the rules of equality tell you that anything you do to one side of the equation must also be done to the other side.

You can consider it as "unwrapping the package". You start at the outside, the last operation applied, and work your way in.

4 0
3 years ago
Find the distance between the following two points: (3,-6) (-1,-8)
Helga [31]
Distance between two points =
√
(
−
1
−
3
)
2
+
(
−
8
−
−
6
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2
6 0
3 years ago
NEED HELP PLEASE ALSO I NEED EXPLANATIONS TO THESE PROBLEMS I WILL MARK BRAINLIEST.
Molodets [167]

Answer:

a) to determine how much Carl gets per hour, divide earnings by hours.

45 / 3 = 15

$15 per hour

b) Carl earns more per hour, because 15 is greater than 12.

3 0
3 years ago
9. Consider the circles with the following equations:
kenny6666 [7]

Answer with Step-by-step explanation:

We are given that

x^2+y^2=(\sqrt 2)^2

(x-3)^2+(y-3)^2=32=(4\sqrt 2)^2

Compare with the equation of circle

(x-h)^2+(y-k)^2=r^2

Where center of circle=(h,k)

r=Radius of circle

a.Center of circle=(0,0)

Radius=\sqrt 2 units

Center of second circle=(3,3)

Radius of second circle=4\sqrt 2 units

b.Distance formula:\sqrt{(x_2-x_1)^2+(y_2-y_1)^2

Using the formula

The distance between the centers of two circle

=\sqrt{(3-0)^2+(3-0)^2}=3\sqrt 2

Hence, the distance between the centers of two circle =3\sqrt 2 units.

c.

Substitute x=-1 and -1

1+1=2=

(1-3)^2+(1-3)^2=32

The circle must be tangent because there is just one point (-1,-1) is common in both circles and satisfied the equations of circle.

8 0
3 years ago
Does anyone know how to do that type of problem? I’m struggling with it :(
ZanzabumX [31]

Step-by-step explanation:

4x+92+2x+4=180

6x+96=180

6x=84

x=14

5y-13+8y+76=180

13y=117

/13

y=9

4 0
4 years ago
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