Given:
A figure of a parallelogram.
The vertex angles are 
.
To find:
The values of a and b.
Solution:
We know that the pairs of consecutive angles of a parallelogram are supplementary angles. It mean their sum is 180 degrees.
(Supplementary angles)
Subtract 10 from both sides.
Divide both sides by 17.
Now,
And,
(Supplementary angles)
Divide both sides by 2.
Therefore, the value of a is 64 and the value of b is 10.
Answer:
Where's the x?
I am assuming that the problem must be
-3 + 42 > 3x
if that is true, then
<u>x < 13</u>.
As this statement is, -3 + 42 > 3 is a true statement because -3 + 42 = 39, and
39 > 3 [39 is always greater than 3]
Step-by-step explanation:
Let me know if you need a step by step.
Answer:
If you need any further help, feel free to let me know
Step-by-step explanation:
The answers are
(8-9)-(9+3)*5=-61
5+(5+5+6)+9=30
(5/3-3)= -4 over 3 or -4/3 or -1.3 or -1 1/3 depends on what your choices are but all those are correct
2*3+(4*2)/2=10
Answer:
Step-by-step explanation:
(-4,0) ; (-7, -14)
![d=\sqrt{(x_{2}-x_{1})^{2}+(y_{2}-y_{1})^{2}}\\\\ =\sqrt{(-7-[-4])^{2}+(-14-0)^{2}}\\\\ =\sqrt{(-7+4)^{2}+(-14)^{2}}\\\\=\sqrt{(-3)^{2}+(-14)^{2}}\\\\=\sqrt{9+196} \\\\=\sqrt{205} \\\\=14.3178](https://tex.z-dn.net/?f=d%3D%5Csqrt%7B%28x_%7B2%7D-x_%7B1%7D%29%5E%7B2%7D%2B%28y_%7B2%7D-y_%7B1%7D%29%5E%7B2%7D%7D%5C%5C%5C%5C%20%3D%5Csqrt%7B%28-7-%5B-4%5D%29%5E%7B2%7D%2B%28-14-0%29%5E%7B2%7D%7D%5C%5C%5C%5C%20%3D%5Csqrt%7B%28-7%2B4%29%5E%7B2%7D%2B%28-14%29%5E%7B2%7D%7D%5C%5C%5C%5C%3D%5Csqrt%7B%28-3%29%5E%7B2%7D%2B%28-14%29%5E%7B2%7D%7D%5C%5C%5C%5C%3D%5Csqrt%7B9%2B196%7D%20%5C%5C%5C%5C%3D%5Csqrt%7B205%7D%20%5C%5C%5C%5C%3D14.3178)
<span>get all your x one on side and y on the opposing side
so we have
xdy=4ydx
dy/y=4dx/x
</span><span>integrate both sides
</span><span>lny=4lnx+C
</span><span> y=e^(4lnx+C)
</span><span>The answer is y=cx^4 </span>
