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Anna007 [38]
4 years ago
5

Analyze the diagram below and complete the instructions that follow.Find m

Mathematics
1 answer:
vladimir2022 [97]4 years ago
3 0
Answer: 70.5°

Solution:

Call B, the measure of the angle CBA

cos(B) = adjacent-leg / hypotenuse = 3 / 9 = 1 / 3

=> B = arc cos (1/3) ≈ 70.5°

I will calculate other measures for you, trying to cover the most common ratios: sine, cosine, tangent

1) (segment CA)^2 + (segment BC)^2 = (hypotenuse)^2

=> (segment CA )^2 = (hypotenuse)^2 - (segment BC)^2 = 9^2 - 3^2 = 81 - 9 = 72

=> segment CA = √72 = 6√2

2) sin(B) = opposite-leg / hypotenuse = 6√2 / 9 =2√2 / 3

3) sin(A) = cos(B) = 1/3

4) cos(A) = sin(B) = 2√2 / 3

5) tan(B) = opposite-leg / adjacent-leg = (2√2 / 3 ) / 3 = 2√2 / 9

6) tang(A) = 3 / (2√2 /3) = 9 /( 2√2) = 9√2 / 4

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If tan theta = 12/5 and cos theta < 0, what is sin theta ?
Talja [164]
1 + tan ² Ф=sec²Ф
1+(12/5)²=sec²Ф
169/25=sec² Ф
sec Ф=⁺₋√(169/25)=⁺₋13/5

sec Ф=1/cos Ф ⇒cosФ=1/sec Ф
 cos Ф>0   ⇔  sec Ф>0  ⇔  sec Ф=+ 13/5

cos Ф=1/secФ
cos Ф=1 / 13/5=5/13

we can calculate the sin Ф, with this method.
sin²Ф + cos²Ф=1  ⇒ sin Ф=⁺₋√(1-cos² Ф)
sin Ф=⁺₋√[1-(5/13)²]=⁺₋12/13
like cos Ф>0 and tan Ф>0   ⇒ sin Ф>0 ⇒sin Ф=12/13

answer: d.12/13

other method
tan Ф=sin Ф / cos Ф
12/5=sin Ф / 5/13
sin Ф=(12/5)*(5/13)=12/13

answer: d.12/13

8 0
3 years ago
Answer to number 6 please
Alenkasestr [34]

Answer:

Step-by-step explanation:

C

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I can h lo just do the message thing and I can probably help
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4 years ago
Hellllppppppeee pleaseeee!!!!!!
Mars2501 [29]

Answer:

Scale Factor = 2

Step-by-step explanation:

ABC is your original triangle and A'B'C' is the dilation. You know these are similar triangles so only one side has to be used to find the scale factor. AB has a length of 3 and A'B' has a length of 6 so you know the side lengths of A'B'C' are going to be 2 times the size of triangle ABC side lengths. This gives you a scale factor of 2.

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3 years ago
Solve 36x^2-22x=14x-9
frutty [35]

x=1/2


i hate the minimum word count

no one comes on here to learn how to do it, we come on here to get answers


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