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MrRissso [65]
3 years ago
11

Expand & simplify: (x - 5)(x + 2)

Mathematics
2 answers:
alexgriva [62]3 years ago
8 0
It’s 10 square two-3x-10
Serjik [45]3 years ago
7 0

Answer:

( x - 5 )( x + 2 )

= x² + 2x - 5x - 10

= x² - 3x - 10

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Calculus Problem
Roman55 [17]

The two parabolas intersect for

8-x^2 = x^2 \implies 2x^2 = 8 \implies x^2 = 4 \implies x=\pm2

and so the base of each solid is the set

B = \left\{(x,y) \,:\, -2\le x\le2 \text{ and } x^2 \le y \le 8-x^2\right\}

The side length of each cross section that coincides with B is equal to the vertical distance between the two parabolas, |x^2-(8-x^2)| = 2|x^2-4|. But since -2 ≤ x ≤ 2, this reduces to 2(x^2-4).

a. Square cross sections will contribute a volume of

\left(2(x^2-4)\right)^2 \, \Delta x = 4(x^2-4)^2 \, \Delta x

where ∆x is the thickness of the section. Then the volume would be

\displaystyle \int_{-2}^2 4(x^2-4)^2 \, dx = 8 \int_0^2 (x^2-4)^2 \, dx \\\\ = 8 \int_0^2 (x^4-8x^2+16) \, dx \\\\ = 8 \left(\frac{2^5}5 - \frac{8\times2^3}3 + 16\times2\right) = \boxed{\frac{2048}{15}}

where we take advantage of symmetry in the first line.

b. For a semicircle, the side length we found earlier corresponds to diameter. Each semicircular cross section will contribute a volume of

\dfrac\pi8 \left(2(x^2-4)\right)^2 \, \Delta x = \dfrac\pi2 (x^2-4)^2 \, \Delta x

We end up with the same integral as before except for the leading constant:

\displaystyle \int_{-2}^2 \frac\pi2 (x^2-4)^2 \, dx = \pi \int_0^2 (x^2-4)^2 \, dx

Using the result of part (a), the volume is

\displaystyle \frac\pi8 \times 8 \int_0^2 (x^2-4)^2 \, dx = \boxed{\frac{256\pi}{15}}}

c. An equilateral triangle with side length s has area √3/4 s², hence the volume of a given section is

\dfrac{\sqrt3}4 \left(2(x^2-4)\right)^2 \, \Delta x = \sqrt3 (x^2-4)^2 \, \Delta x

and using the result of part (a) again, the volume is

\displaystyle \int_{-2}^2 \sqrt 3(x^2-4)^2 \, dx = \frac{\sqrt3}4 \times 8 \int_0^2 (x^2-4)^2 \, dx = \boxed{\frac{512}{5\sqrt3}}

7 0
2 years ago
If Rachel now owes a quarter of the money that she once owed, what could you do to find how much money she owes now?
MakcuM [25]
Divide what she owed is the right answer
8 0
3 years ago
Read 2 more answers
find two consecutive odd numbers such that the sum of the larger number and twice the smaller number is 27 less then four times
soldier1979 [14.2K]

N is an odd integer

The Next Larger is N+2

N+2 + 2N = -27 + 4N

3N + 2 = 4N - 27

0 = 4N - 27 - 3N - 2

0 = N - 29

N = 29

They are 29 and 31.

31 + 2(29) = 4(29) - 27

31 + 58 = 89 = 116 - 27  yes it works

4 0
3 years ago
What is the midpoint of the line segment (-8,-7) and (-7,-8)
goblinko [34]
The answer is (-7.5, -7.5)
3 0
3 years ago
Multiply.<br><br> At 6 ½¢ per pound of string beans, how much does 8 pounds cost?
zzz [600]
52 I think , because 6 1/2 x 8 is 52
4 0
3 years ago
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