The two parabolas intersect for

and so the base of each solid is the set

The side length of each cross section that coincides with B is equal to the vertical distance between the two parabolas,
. But since -2 ≤ x ≤ 2, this reduces to
.
a. Square cross sections will contribute a volume of

where ∆x is the thickness of the section. Then the volume would be

where we take advantage of symmetry in the first line.
b. For a semicircle, the side length we found earlier corresponds to diameter. Each semicircular cross section will contribute a volume of

We end up with the same integral as before except for the leading constant:

Using the result of part (a), the volume is

c. An equilateral triangle with side length s has area √3/4 s², hence the volume of a given section is

and using the result of part (a) again, the volume is

N is an odd integer
The Next Larger is N+2
N+2 + 2N = -27 + 4N
3N + 2 = 4N - 27
0 = 4N - 27 - 3N - 2
0 = N - 29
N = 29
They are 29 and 31.
31 + 2(29) = 4(29) - 27
31 + 58 = 89 = 116 - 27 yes it works
The answer is (-7.5, -7.5)
52 I think , because 6 1/2 x 8 is 52