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Margaret [11]
3 years ago
13

Does anyone wanna be friends lol?

Mathematics
2 answers:
USPshnik [31]3 years ago
7 0

Answer:

hahaha me

Step-by-step explanation:

...actually how old are you though lol

netineya [11]3 years ago
7 0

do you have any questions?

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How to solve 5x+2=11/3 step by step please
AveGali [126]
Soo you subtract 2 from 11/3 which is 1.6 then you divide 5 from that number so the answer is 0.33 repeating
3 0
3 years ago
Find the length of the third side. If
Bumek [7]

This is the diagram

Answer:

b=9

Step-by-step explanation:

This photo is the diagram now for the solution

using the Pythagoras theorem

we know that

C²=a²+b²

now we are looking for the third side we are given the value of A which is 6 and C which is 3√13 then that suppose that we are looking for b

we then make b the subject of the formula

C²=A²+B²

B²=C²-A²

B=√C²-√A²

then we substitute for the values

B=√(3√13)²-√6²

B=√117-√36

B=√81

B=9

please rate as brainliest

and please if you should follow me i will follow you back

6 0
1 year ago
your sister can get $30 per day for selling clothes at the market. but she has to $60 at first for renting a stand. you can get
ella [17]
Day Sis you
1 -30 20
2 0 40
3 30 60
4 60 80
5 90 100
6 120 120

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8 0
3 years ago
Read 2 more answers
HELP!!!!! ME!!! NEED HELP!
Katena32 [7]
Y = -4x + 2
3x + 2y = 6 (or in y-intercept form y=-3/2x + 3)

2x - y = 7 equals y = 2x -7 in y-intercept form. This means that the line has a positive slope and therefore goes upwards. This cannot be a potential equation because the line shown is clearly pointing downwards.

y=5 indicates that the line is a horizontal line that neither points upwards or downwards. This cannot be a potential equation because the line is pointing downwards. 

The only possible equations left are y= -4x + 2 and 3x + 2y = 6, both of which graph a line pointing downwards because their slopes are negative. Hope this helps!
6 0
3 years ago
What is the quotient of 11/12 ÷ 5/7 ?
alexandr402 [8]
Your answer is 77/60 or 1 17/60
6 0
3 years ago
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