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3 years ago

What equation represents a circle with a center at (-3, -5) and a radius of 6 units

Mathematics

1 answer:

kupik [55]3 years ago

3 0

Answer:

(x+3)^2 + (y +5)^2 = 36

Step-by-step explanation:

We can write the equation of a circle with the formula

(x-h)^2 + (y-k)^2 = r^2 where (h,k) is the center and r is the radius

(x- -3)^2 + (y - -5)^2 = 6^2

(x+3)^2 + (y +5)^2 = 6^2

(x+3)^2 + (y +5)^2 = 36

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1. what is 10% of 20? 2.What is 5% of 10?

Airida [17]

Hello,

Shall we begin?

1. what is 10% of 20? = 20 * 0.1 = 2
2.What is 5% of 10? = 10 * 0.05 = 0,5
3. What is 25% of 100? = 100 * 0,25 = 25
4. What is 15% of 50? = 50 * 0.15 = 7,5
5. What is 30% of 60? = 60 * 0,3 = 18
6. What is 50% of 80? = 80 * 0,5 = 40
7. What is 20% of 120? = 120 * 0,2 = 24
8. What is 35% of 70? = 70 * 0,35 = 24.5
9. What is 75% of 150? = 150 * 0,75 = 112.5
10. What is 60% of 90? = 90 * 0,6 = 54
11. What is 40% of 40? = 40 * 0,4 = 16
12. What is 55% of 110? = 110 * 0.55 = 60.5
13. What is 80% of 130? = 130 * 0,80 = 104

5 0

3 years ago

Read 2 more answers

An hourglass consists of two sets of congruent composite figures on either end. Each composite figure is made up of a cone and a

belka [17]

Answer: third option 268.8

Explanation:

For this kind of proble it is very important that you attach the figure because it contains important information to understand the question.

I have attached the figure for better understanding.

1) The top portion (and the bottom is congruent but rotated 180°) of the hourglass is a figure equivalent to a cylinder on top and a cone on bottom.

So the total volume contained in the top portion is the volume of a cylinder + the volume of a cone.

This is how you calculate the volume of the top portion:

1) The height of the cylinder is 54 mm - 18 mm = 36 mm

2) The formula for the volume of a cylinder is V = π (radius)^2 * height

radius = 8 mm
height = 36 mm

=> V = π(8mm)^2 * 36 mm = 2304π (mm)^3

3) The formula for the volume of a cone is V = (1/3)π(radius)^2 * height

radius = 8 mm
height = 18 mm

V = (1/3)π(8mm)^2 * 18 mm = 384π (mm)^3

4) The total volume of the top portion is volumen of the cylindrical part + voume of the cone:

Total voluem = 2304π (mm)^3 + 384π (mm)^3 = 2688π (mm)^3

5) To find the number of seconds <span>it take until all of the sand has dripped to the bottom of the hourglass you have to divide the total volumen of sand by the rate:

time in seconds = total volume of sand / rate of dripping

time in seconds = [2688 π (mm)^3 ] / [10π (mm)^3 / s] = 268.8 s

That is the answer: 268.8 s
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4 0

3 years ago

Read 2 more answers

If DF = 9x -39 find EF

Klio2033 [76]

|DF| = |DE| + |EF|

|DF| = 9x -36

|DE| = 47

|EF| = 3x+10

Substitute:

9x - 39 = 47 + 3x + 10

9x - 39 = 3x + 57 |+39

9x = 3x + 96 |-3x

6x = 96 |:6

x = 16

Put the value of x to the equation |EF| = 3x + 10

|EF| = (3)(16) + 10 = 48 + 10 = 58

Answer: |EF| = 58

7 0

3 years ago

Read 2 more answers

(5) Find the Laplace transform of the following time functions: (a) f(t) = 20.5 + 10t + t 2 + δ(t), where δ(t) is the unit impul

Aloiza [94]

Answer

(a) $F(s) = \frac{20.5}{s} - \frac{10}{s^2} - \frac{2}{s^3}$

(b) $F(s) = \frac{-1}{s + 1} - \frac{4}{s + 4} - \frac{4}{9(s + 1)^2}$

Step-by-step explanation:

(a) $f(t) = 20.5 + 10t + t^2 +$ δ(t)

where δ(t) = unit impulse function

The Laplace transform of function f(t) is given as:

$F(s) = \int\limits^a_0 f(s)e^{-st} \, dt$

where a = ∞

=> $F(s) = \int\limits^a_0 {(20.5 + 10t + t^2 + d(t))e^{-st} \, dt$

where d(t) = δ(t)

=> $F(s) = \int\limits^a_0 {(20.5e^{-st} + 10te^{-st} + t^2e^{-st} + d(t)e^{-st}) \, dt$

Integrating, we have:

=> $F(s) = (20.5\frac{e^{-st}}{s} - 10\frac{(t + 1)e^{-st}}{s^2} - \frac{(st(st + 2) + 2)e^{-st}}{s^3} )\left \{ {{a} \atop {0}} \right.$

Inputting the boundary conditions t = a = ∞, t = 0:

$F(s) = \frac{20.5}{s} - \frac{10}{s^2} - \frac{2}{s^3}$

(b) $f(t) = e^{-t} + 4e^{-4t} + te^{-3t}$

The Laplace transform of function f(t) is given as:

$F(s) = \int\limits^a_0 (e^{-t} + 4e^{-4t} + te^{-3t} )e^{-st} \, dt$

$F(s) = \int\limits^a_0 (e^{-t}e^{-st} + 4e^{-4t}e^{-st} + te^{-3t}e^{-st} ) \, dt$

$F(s) = \int\limits^a_0 (e^{-t(1 + s)} + 4e^{-t(4 + s)} + te^{-t(3 + s)} ) \, dt$

Integrating, we have:

$F(s) = [\frac{-e^{-(s + 1)t}} {s + 1} - \frac{4e^{-(s + 4)}}{s + 4} - \frac{(3(s + 1)t + 1)e^{-3(s + 1)t})}{9(s + 1)^2}] \left \{ {{a} \atop {0}} \right.$

Inputting the boundary condition, t = a = ∞, t = 0:

$F(s) = \frac{-1}{s + 1} - \frac{4}{s + 4} - \frac{4}{9(s + 1)^2}$

3 0

3 years ago

7. A seed company planted a floral mosaic

jenyasd209 [6]

Answer:

w = 160, L = 50

Step-by-step explanation:

Length = 50 feet

Width = 160 feet

First Find the Length

w = l + 110

P=2w+2l

420=2w+2l

420=2(l+110)+2l

420=2l+220+2l

4l=200

l=50

Finding the Width

w=(50)+110

w=160

7 0

2 years ago