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allsm [11]
3 years ago
5

two men A and B stand on opposite sides of a 100 metre tower.A observes the angle of elevation of the top of the tower as 45 and

B observes it as 30 . how far apart are the men?​
Mathematics
1 answer:
Zepler [3.9K]3 years ago
8 0

9514 1404 393

Answer:

  273 m

Step-by-step explanation:

The tower represents the short side of a 30°-60°-90° right triangle. The distance from the tower represents the long leg, not the hypotenuse, of that triangle. It is √3 times the short side. In this geometry, man B is 100√3 = 173.2 meters from the tower.

The tower represents one of two congruent sides of a 45°-45°-90° right triangle. Man A will be standing 100 meters from the tower.

The distance between A and B is 100 +173.2 = 273.2 meters. The men are about 273 meters apart.

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