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Zina [86]
3 years ago
5

What’s the answer and how to solve this problem

Mathematics
1 answer:
irakobra [83]3 years ago
7 0
That's a long problem for five points.
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What is a factor of both 28 and 49
sdas [7]
Factor 28 and 49

28
1*14
1*2*7

49
7*7

7 is the answer
5 0
3 years ago
Can you help givie full info thanks
liubo4ka [24]

Answer:

13

Step-by-step explanation:

Using long division, you can multiply each given value by 100 to eliminate the decimals:

2.08x100=208

0.16x100=16

OR (calculator method)

2.08÷0.16=13

You must divide the amount of food per cat by the total amount of food available to determine how many cats can be fed.  This division can be done using a calculator.

OR

5 0
2 years ago
Read 2 more answers
The sides of a triangle are in the ratio of 2:3:4. If the measure of the shortest side of the triangle is 12 centimeters, what i
Scorpion4ik [409]
To answer this, we let x some factor that would agree or make the ratio given true. We calculate as follows:

<span>2:3:4
2x:3x:4x

2x = 12
x = 6 

Therefore, the length of the longest side would be 4x = 4(6) = 24 cm, third option.</span>
3 0
3 years ago
Read 2 more answers
Zoe has 4 cucumbers she grew in her garden. She wants to share them equally among 3 of her neighbors.
dedylja [7]

4 divided by 3 = a whole and 3 repeated more than 4 times

(to use the number 4)

:D

8 0
2 years ago
$13,957 is invested, part at 7% and the rest at 6%. If the interest earned from the amount invested at 7% exceeds the interest e
ch4aika [34]

Answer:

The Amount invested at 7% interest is $12,855

The Amount invested at 6% interest = $1,102  

Step-by-step explanation:

Given as :

The Total money invested = $13,957

Let The money invested at 7% = p_1  = $A

And The money invested at 6% = p_2 = $13957 - $A

Let The interest earn at 7% = I_1

And The interest earn at 6% = I_2

I_1 -  I_2 = $833.73

Let The time period = 1 year

Now,<u> From Simple Interest method</u>

Simple Interest = \dfrac{\textrm principal\times \textrm rate\times \textrm time}{100}

Or,  I_1 = \dfrac{\textrm p_1\times \textrm 7\times \textrm 1}{100}

Or,  I_1 = \dfrac{\textrm A\times \textrm 7\times \textrm 1}{100}

And

I_2 = \dfrac{\textrm p_2\times \textrm 6\times \textrm 1}{100}

Or,  I_2 = \dfrac{\textrm (13,957 - A)\times \textrm 6\times \textrm 1}{100}

∵  I_1 -  I_2 = $833.73

So, \dfrac{\textrm A\times \textrm 7\times \textrm 1}{100} -  \dfrac{\textrm (13,957 - A)\times \textrm 6\times \textrm 1}{100} = $833.73

Or, 7 A - 6 (13,957 - A) = $833.73 × 100

Or, 7 A - $83,742 + 6 A = $83373

Or, 13 A = $83373 + $83742

Or, 13 A = $167,115

∴ A = \dfrac{167115}{13}

i.e A = $12,855

So, The Amount invested at 7% interest = A = $12,855

And The Amount invested at 6% interest = ($13,957 - A) = $13,957 - $12,855

I.e The Amount invested at 6% interest = $1,102

Hence,The Amount invested at 7% interest is $12,855

And The Amount invested at 6% interest = $1,102   . Answer

8 0
3 years ago
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