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rodikova [14]
3 years ago
5

Thank u for answering !​

Mathematics
1 answer:
maxonik [38]3 years ago
6 0

Answer:

1. C

2. A

3. B

4. B

5. A

6. A

Step-by-step explanation:

you will answer the rest, sorry if i was rude

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5y-x=10 solve for y
shusha [124]
5y-x=10\\\\ 5y=10+x \ |:5 \ Both \ sides \\\\ y=\frac{10}{5}+\frac{x}{5}\\\\ y=2+\frac{x}{5}

because
5y-x=5(2+\frac{x}{5})-x=5\cdot 2 +\frac{x}{\not5}\cdot 5 - x= 10+x-x=10



3 0
3 years ago
What is the slope of the line that passes through the points (8,-4) and (6,2)
padilas [110]

Answer: M= slope

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Step-by-step explanation:

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8 0
3 years ago
Deviation is the difference between any value and the mean of the set.
faust18 [17]
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7 0
3 years ago
5<br> 0 = - in<br> =<br> in quadrant II<br> Given cos =<br> Find sin<br> 3
____ [38]

Answer:

sinΘ = \frac{2}{3}

Step-by-step explanation:

using the identity

sin²x + cos²x = 1  ( subtract cos²x from both sides )

sin²x = 1 - cos²x ( take square root of both sides )

sinx = ± \sqrt{1-cos^2x}

given

cosΘ = - \frac{\sqrt{5} }{3} , then

sinΘ = ± \sqrt{1-(-\frac{\sqrt{5} }{3})^2 }

        = ± \sqrt{1-\frac{5}{9} }

        = ± \sqrt{\frac{4}{9} }

        = ± \frac{2}{3}

since Θ is in quadrant II where sinΘ > 0 , then

sinΘ = \frac{2}{3}

7 0
2 years ago
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Area of a square:

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= (6x + 1) ^2

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8 0
2 years ago
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