Let after t hours the distances D1<span> traveled by car A</span>
=> D1<span> = 30 t</span>
Car B starts at 10 am and will, therefore, have spent one hour less than car A when it passes it.
After (t - 1) hours, distance D2<span> traveled by car B </span>
=> D2<span> = 40 (t - 1)</span>
When car B passes car A, they are at the same distance from the starting point and therefore<span> D1 = D2 </span>
=> 30 t = 40 (t - 1)
Solve the equation for t,
=> 30 t = 40t - 40
=> 10 t = 40
=> t = 4
=><span> Car B passes car A at = 9 + 4 = 13 pm.</span>
Chord because the radius is the center of the circle to a side and diameter is the length across a circle through the center point so chord is the correct answer! I hope this helps! :)
<h2>
Answer with explanation:</h2>
Rolle's Theorem states that:
If f is a continuous function in [a,b] and is differentiable in (a,b)
such that f(a)=f(b)
Then there exist a constant c in between a and b i.e. c∈[a,b]
such that: f'(c)=0
Here we have the function f(x) as:
where x∈[-1,3]
- Since the function f(x) is a polynomial function hence it is continuous as well as differentiable over the interval [-1,3].
Also,
f(-1)=15
(Since,
)
and f(3)=15
( Since,
)
Hence, there will exist a c∈[-1,3] such that f'(c)=0

Hence, the c that satisfy the conclusion is: c=1
Step-by-step explanation:
=3a+a-36+4a
=4a+4a-36
=8a-36
=4(2a-9)