Answer:
x+3y-6=0
Step-by-step explanation:
given eqn is y=3x-2 which is 3x-y-2=0
the eqn of line perpendicular to given eqn is -x+3y+k=0
it passes through (6,4)
-6+3*4+k=0
or,. -6+12+k=0
or, k= -6
therefore, the eqn of line perpendicular to given eqn is x+3y-6=0
Step-by-step explanation: i will try t look for him but i have not seen him at all
Answer:
y=-3x+15
Step-by-step explanation:
the midpoint of UV (using the midpoint formula) is (3,6)
the slope of UV= 4/12= (1/3)
perpendicular slope is -3
now find line with slope -3 passing (3,6)
y-6=-3(x-3)
y=-3x+15
Answer:
C. the lines are perpendicular