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nataly862011 [7]
3 years ago
13

Match the inequality to its graph

Mathematics
1 answer:
UkoKoshka [18]3 years ago
5 0

-1 > -4

3 <u>></u> 0

1 <u>></u> -2

3 > -5

I don't understand the second one sorry.

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What is the value of (-3+3i)+(-2+3i)
Yanka [14]

Answer: i=<u>  5  </u>

                  6

Step-by-step explanation:

(-3+3i)+(-2+3i)

-3+3i-2+3i=0

3i+3i=3+2

6i=5

i=<u>  5  </u>

   6

3 0
3 years ago
Thank you for helping
max2010maxim [7]

Answer:

It is clear that the multiplication of two values in Eq A is done to get the LCM while same method is not applied for eq B .

Step-by-step explanation:

Given as :

The two statement are

A) The LCM of 5 , 13 = 65

Here The multiple of 5 = 1 × 5

And The multiple of 13 =  1 × 13

So, Applying prime factor method,

least common multiple = product of height power of all factors that occur in resolution

So, LCM = 1 × 5 × 1 × 13

i.e LCM = 65

<u>Again</u>

B) The LCM of 6 , 8 = 24

Here The multiple of 6 = 1 × 2 × 3

And The multiple of 8 =  1 × 2 × 2 × 2

i.e  The multiple of 8 =  1 × 2³

So, Applying prime factor method,

least common multiple = product of height power of all factors that occur in resolution

So, LCM = 2³ × 3

i.e LCM = 24

Hence, It is clear that the multiplication of two values in Eq A is done to get the LCM while same method is not applied for eq B . Answer

6 0
4 years ago
Please give full explanation
Alex

S (ABCD) = S (ABC) + S (ADC)

_____________________________________________

<h2>Reminder :</h2>

Area of the triangle = ½ × base × height

_____________________________________________

Thus :

S (ABCD) = ( \frac{1}{2}   \times 10 \times 3) + ( \frac{1}{2}  \times 10 \times 5) \\

S (ABCD) = 15 + 25

S (ABCD) = 40 \:  \:  {cm}^{2}

There you go...

Have a great day ❤

4 0
2 years ago
An extra large pizza has v pieces. if 6 friends divide it evenly, write an expression to show how many pieces each one will get.
VLD [36.1K]

Answer:

y= v/6

Step-by-step explanation:

y stands for pieces

8 0
4 years ago
What is the coefficient of the fourth term in the expansion of (x - y)^6?
Zarrin [17]
<span>If you're aware of the binomial theorem, you have that:
</span>(x-y)^6=\sum_{k=0}^{6}\binom{6}{6-k}x^k(-1)^{6-k}y^{6-k}
(x-y)^6=\sum_{k=0}^{6}\binom{6}{k}x^k(-1)^{k}y^{6-k}

The fourth term is then the case k=3, from which:
c_{3}=\binom{6}{3}x^3(-1)^3y^3= \frac{6!}{3!(6-3)!} * (-x^3y^3)=- \frac{720}{36}x^3y^3=-20x^3y^3
3 0
4 years ago
Read 2 more answers
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