Answer:
150 is ans
Step-by-step explanation:
ok bro my answer never wrong ok
Answer:
Since L.H.S = R.H.S = 0, for both and , y₁ and y₂ both satisfy the equation y" - y = 0 and are thus solutions to the differential equation.
Step-by-step explanation:
To check whether the given functions are solutions the given differential equation, we differentiate the functions and then insert it into the given equation.
So y" - y = 0 and
Substituting these values of y and y" into the left hand side of the equation, we have
y" - y
Since L.H.S = R.H.S
So is a solution of the differential equation.
When
Substituting y and y" into the left hand side of the equation, we have
y" - y
Since L.H.S = R.H.S
So, is a solution of the differential equation.
Answer:
x = 0
Step-by-step explanation:
if 2y + x = 4
we can assume that y = 2
if y - 3x = 2
it means 2 - 0 = 2
therefore x = 0
Answer:
C = 20
Step-by-step explanation:
What happens if simultaneous Equations have two of the same variable like below? How would I solve it?
6A + 4B + 5C = 390
6A + 4B + 5.75C = 405
Step 1
We solve for C first
6A + 4B + 5C = 390....Equation 1
6A + 4B + 5.75C = 405... Equation 2
We substract Equation 1 from Equation 2
0.75C = 15
C = 15/0.75
C = 20