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lesantik [10]
3 years ago
8

Solve the equation for y: x=2y-3

Mathematics
1 answer:
astraxan [27]3 years ago
6 0
Y=1/2x+3/2
You have to add the 3 over and then divide both of the sides by 2 to isolate the y.
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Suppose Z has a normal distribution with a mean of 10.0 and a standard deviation of 5.0 what is the P(2.0
il63 [147K]

Answer:

.0548

Step-by-step explanation:

(2-10)/5= -1.6

go to a ztable and get .0548

4 0
3 years ago
Find the values of x and y - i will give brainliest if right
kherson [118]

Answer:

itd x=68 and y=5 I apolgize if its wrong

4 0
3 years ago
Triangles A B C and R M Q are shown. Angles C A B and M R Q are 29 degrees. Angles A B C and R M Q are 116 degrees. What additio
Svetlanka [38]

Answer:

Therefore, the two options for triangles to be congruent using AAS are

1. BC ≅ MQ       (Additional information)

2. AC ≅ RQ       (Additional information)

Step-by-step explanation:

Given:

∠CAB =∠MRQ = 29°

∠ABC = ∠RMQ = 116°

To Prove:

Δ ABC ≅ ΔRMQ  by AAS congruence test which additional information is required

Proof:

<u>Case 1.</u>

In  Δ ABC and Δ RMQ

∠CAB =∠MRQ = 29°      ……….{Given}

∠ABC = ∠RMQ = 116°     ..……..{Given}

BC ≅ MQ                        ……….{Additional information required}

Δ ABC ≅ Δ RMQ ….{By Angle-Angle-Side congruence test}

<u>Case 2.</u>

In  Δ ABC and Δ RMQ

∠CAB =∠MRQ = 29°      ……….{Given}

∠ABC = ∠RMQ = 116°     ..……..{Given}

AC ≅ RQ                        ……….{Additional information required}

Δ ABC ≅ Δ RMQ ….{By Angle-Angle-Side congruence test}

Therefore, the two options for triangles to be congruent using AAS are

1. BC ≅ MQ       (Additional information)

2. AC ≅ RQ       (Additional information)

3 0
4 years ago
Read 2 more answers
Compute the standard error for sample proportions from a population with proportion p= 0.55 for sample sizes of n=30, n=100 and
Pani-rosa [81]

Given Information:

Population proportion = p =  0.55

Sample size 1 = n₁ = 30

Sample size 2 = n₂ = 100

Sample size 3 = n₃ = 1000

Required Information:

Standard error = σ = ?

Answer:

$ \sigma_1 = 0.091 $

$ \sigma_2 = 0.050 $

$ \sigma_3 = 0.016 $

Step-by-step explanation:

The standard error for sample proportions from a population is given by

$ \sigma =  \sqrt{\frac{p(1-p)}{n} } $  

Where p is the population proportion and n is the sample size.

For sample size n₁ = 30

$ \sigma_1 =  \sqrt{\frac{p(1-p)}{n_1} } $

$ \sigma_1 =  \sqrt{\frac{0.55(1-0.55)}{30} } $

$ \sigma_1 = 0.091 $

For sample size n₂ = 100

$ \sigma_2 =  \sqrt{\frac{p(1-p)}{n_2} } $

$ \sigma_2 =  \sqrt{\frac{0.55(1-0.55)}{100} } $

$ \sigma_2 = 0.050 $

For sample size n₃ = 1000

$ \sigma_3 =  \sqrt{\frac{p(1-p)}{n_3} } $

$ \sigma_3 =  \sqrt{\frac{0.55(1-0.55)}{1000} } $

$ \sigma_3 = 0.016 $

As you can notice, the standard error decreases as the sample size increases.

Therefore, the greater the sample size lesser will be the standard error.

8 0
4 years ago
Five friends bought admission tickets to the museum and a box lunch. the cost of each admission ticket was $11.75. each box lunc
Ne4ueva [31]
5 x 11.75 = $58.75 (admission ticket)
5 x 5 = $25.00 (box lunch)

$25.00 + $58.75 = $83.73 (total)
3 0
3 years ago
Read 2 more answers
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