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3 years ago

12

Which numbers are solutions to the inequality -3x-3<_ 6 ? Check all of the boxes that apply.

1 answer:

Stells [14]3 years ago

5 0

Answer:

$x\geq -3$

Step-by-step explanation:

$-3x-3\leq 6$

$+3$ $+3$

$-3x\leq 9$

$\frac{-3x}{-3} \leq \frac{9}{-3}$

$x\geq -3$

*View attached graph*

Hope this helps!

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Suppose that X is a geometric random variable with p=2/3<br> Solve for P (X=1 ∩ X ≥ 3)?

Tcecarenko [31]

$X$ can't simultaneously be equal to 1 and larger than 2, so the probability must be zero.

Did you mean to find the probability of the union? In that case, since the events are mutually exclusive, you would be able to write

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$=\mathbb P(X=1)+1-\mathbb P(X$
$=\mathbb P(X=1)+1-\mathbb P(X\le2)$
$=1+f_X(1)+F_X(2)$

where $f_X(x)$ is the probability density function and $F_X(x)$ is the cumulative distribution function for the random variable $X$ .

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4 years ago

Is 8/10 equivalent to 4/5

nordsb [41]

Yes 8/10 is equivalent to 4/5 or 16/20 ...

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3 years ago

Read 2 more answers

2) Lisa is ordering sand from the Internet, On one site she found sand on sale for

Anastasy [175]

For this case we must find the unit cost (dollars per pound) of each site and then compare.

We take into account that:

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Site 1:

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Site 2:

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Thus, the best deal is on site 2.

ANswer:

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4 years ago

What is one of the zeros of the

Sphinxa [80]

Answer:

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Step-by-step explanation:

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3 years ago

There are 16 entrees available at a restaurant. From these, Archie is to choose 6 for his party. How many groups of 6 entrees ca

goblinko [34]

Answer: 8008

Step-by-step explanation:

Total entrees = 16

Number of entrees to choose = 6

Since order does not matter , so we combinations .

Number of combinations to choose r things out of n = $C(n,r)=\dfrac{n!}{r!(n-r)!}$

Then, total ways to choose 6 entrees = $C(16,6)=\dfrac{16!}{6!10!}$

$=\dfrac{16\times15\times14\times13\times12\times11\times10!}{(720)10!}\\\\= 8008$

Hence, the required number of ways= 8008

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3 years ago