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3 years ago

Mason asks his friends at school to do his questionnaire. This may not be a good sample to use.

1 answer:

max2010maxim [7]3 years ago

5 0

The sample is his friends. They might be the same group of interests. The sample needs to be random. Even if he went around and grabbed random people he may not have known at his school, it still wouldn't be random bc they could all be bias towards a local sports team or have different interests than someone from somewhere else

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Mr and mrs Gomez are buying carpet for their square shaped bedroom which measures 7 yd along each wall the carpet is $21 per squ

Andreas93 [3]

Answer:

Step-by-step explanation: The area of the bedroom is

A=7yd^2

The total cost is the sum of the price rates times this area.

C=A•($21+$5)/yd^2

where C is total cost.

C=7yd^2•($21+$5)/yd^2

C=$182

3 0

3 years ago

Answer the questions below about the quadratic function.

Korolek [52]

Given the function $f(x)=3x^2-18x+23$ . The above function can be written as

$f(x)=3x^2-18x+23\\ f(x)=3(x^2-6x)+23\\ f(x)=3(x^2-6x+9-9)+23\\ f(x)=3(x-3)^2-27+23\\ f(x)=3(x-3)^2-4$

a)Now, the function $f(x)=3(x-3)^2-4$ has minimum value since the coefficient of $(x-3)^2$ is $3>0$ .

b) The minimum value of the function occurs at $x=3$ and its value is

$f(3)=3(3-3)^2-4 =-4$

c)The minimum value of the function occurs at $x=3$ .

6 0

3 years ago

Here is a picture of a ferris wheel. It has a diameter of 80 meters. On the picture, draw and label a diameter. What do I do????

Furkat [3]

Answer:

Draw a line directly through the center of the circle. That is the diameter.

Step-by-step explanation:

Hope this helps! Pls give brainliest!

5 0

3 years ago

A right circular cylinder is inscribed in a sphere with diameter 4cm as shown. If the cylinder is open at both ends, find the la

SOVA2 [1]

Answer:

$8\pi\text{ square cm}$

Step-by-step explanation:

Since, we know that,

The surface area of a cylinder having both ends in both sides,

$S=2\pi rh$

Where,

r = radius,

h = height,

Given,

Diameter of the sphere = 4 cm,

So, by using Pythagoras theorem,

$4^2 = (2r)^2 + h^2$ ( see in the below diagram ),

$16 = 4r^2 + h^2$

$16 - 4r^2 = h^2$

$\implies h=\sqrt{16-4r^2}$

Thus, the surface area of the cylinder,

$S=2\pi r(\sqrt{16-4r^2})$

Differentiating with respect to r,

$\frac{dS}{dr}=2\pi(r\times \frac{1}{2\sqrt{16-4r^2}}\times -8r + \sqrt{16-4r^2})$

$=2\pi(\frac{-4r^2+16-4r^2}{\sqrt{16-4r^2}})$

$=2\pi(\frac{-8r^2+16}{\sqrt{16-4r^2}})$

Again differentiating with respect to r,

$\frac{d^2S}{dt^2}=2\pi(\frac{\sqrt{16-4r^2}\times -16r + (-8r^2+16)\times \frac{1}{2\sqrt{16-4r^2}}\times -8r}{16-4r^2})$

For maximum or minimum,

$\frac{dS}{dt}=0$

$2\pi(\frac{-8r^2+16}{\sqrt{16-4r^2}})=0$

$-8r^2 + 16 = 0$

$8r^2 = 16$

$r^2 = 2$

$\implies r = \sqrt{2}$

Since, for r = √2,

$\frac{d^2S}{dt^2}=negative$

Hence, the surface area is maximum if r = √2,

And, maximum surface area,

$S = 2\pi (\sqrt{2})(\sqrt{16-8})$

$=2\pi (\sqrt{2})(\sqrt{8})$

$=2\pi \sqrt{16}$

$=8\pi\text{ square cm}$

4 0

3 years ago

Need help on this quickly! i have 2 more questions like this that i will post if it lets me.

AfilCa [17]

Answer:

x=5 , y=12

Angle 3=140

Angle 4=100

4 0

3 years ago