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3 years ago

What is the relationship between the two expressions: 1/2 +3/4 and 10(1/2 + 3/4)

Mathematics

1 answer:

Harlamova29_29 [7]3 years ago

7 0

9514 1404 393

Answer:

the latter is 10 times the former

Step-by-step explanation:

The latter expression is the same as the former expression, but with a factor of 10 multiplying it. The second expression is 10 times the first.

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A bus covers a distance of 90km at a uniform speed. Had the speed been 15km/hour it would have taken 30 minutes less for the jou

Brrunno [24]

Answer:

Step-by-step explanation

Let's say d = distance, r = speed and t = time

We know the distance formula is :

distance = speed x time

d = r multiplied by t

d = rt

If the speed is 15km/hr, the time would be 30 minutes shorter.

Since d = rt,

90 = 15t

t = 6,

This means the time taken for the bus to complete the journey at 15km/hr would be 6hrs.

Originally though, the journey takes 30 minutes longer.

So we can say t = 6.5 hrs , and we know d = 90

Now we use the distance formula:

d = rt, since we want to find the original speed, we want to find r.

Speed = distance/time

r = d/t

r = 90/6.5

r = 180/13

Therefore the original speed is 180/13 km/hr

4 0

3 years ago

What number is 7 units to the left of -1?

expeople1 [14]

7 unit to the left, means it is 7 less than -1.
-1-7 = -8

Ans: -8

7 0

3 years ago

Using calculus, it can be shown that if a ball is thrown upward with an initial velocity of 16 ft/s from the top of a building 7

Karolina [17]

Answer:

[0, 7]

Step-by-step explanation:

We want the height to be greater than or equal to 32 ft, so ...

704 +16t -16t^2 ≥ 32

t^2 -t -42 ≤ 0 . . . . . . . . . . . subtract 32, divide by -16

(t -7)(t +6) ≤ 0

This inequality will be true for values of t between -6 and +7. Since we're only concerned with times t ≥ 0, the appropriate solution interval is ...

0 ≤ t ≤ 7 . . . . [0, 7] in interval notation

6 0

3 years ago

Can you help me???????????????????

lora16 [44]

Answer:

I know the surface area is 120... don't know about volume

5 0

3 years ago

Rationalize the denominator of \frac{1 \sqrt{3}}{1-\sqrt{3}}. When you write your answer in the form A B\sqrt{C}, where A, B, an

kobusy [5.1K]

Answer:

The value of ABC is 6.

Step-by-step explanation:

Consider the expression

$\frac{1+\sqrt{3}}{1-\sqrt{3}}$

Rationalize the denominator.

$\frac{1+\sqrt{3}}{1-\sqrt{3}}\times \frac{1+\sqrt{3}}{1+\sqrt{3}}$

$\frac{(1+\sqrt{3})^2}{1^2-(\sqrt{3})^2}$

$\frac{1^2+(\sqrt{3})^2+2\sqrt{3}}{1-3}$

$\frac{1+3+2\sqrt{3}}{-2}$

$\frac{4+2\sqrt{3}}{-2}$

$\frac{4}{-2}+\frac{2\sqrt{3}}{-2}$

$-2-\sqrt{3}$ ..... (1)

The answer in the form

$A+B\sqrt{C}$ .... (2)

On comparing (1) and (2), we get

$A=-2,B=-1,C=3$

We need to find the value of ABC.

$ABC=(-2)(-1)(3)=6$

Therefore the value of ABC is 6.

7 0

3 years ago