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3 years ago

Two charged objects, A and B, exert an electric force on each other. What happens if the distance between them is increased?

Physics

2 answers:

notsponge [240]3 years ago

8 0

Answer: option c) the electric force between them decreases.

Explanation:

The electric force that two charged objects exert on each other follows Coulomb's law: the electric force is proportional to the product of the magnitudes of the charges and inversely proportional to the square of the distance that separate the charges.

Mathematically, that is:

Fe = K q₁ q₂ / d²

Hence, you conclude that if the distance between the charges is increased, the electric force will decrease.

gulaghasi [49]3 years ago

5 0

<span>Two charged objects, A and B, exert an electric force on each other. What happens if the distance between them is increased? a) the charge on B decreases b) the charge on B increases c) the electric force between them decreases d) the electric force between them increses</span>

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3 years ago

What is the mass of a sample of water that takes 2000 kJ of energy to boil into steam at 373 K? The latent heat of vaporization

GREYUIT [131]

Answer : The mass of a sample of water is, 888.89 grams

Explanation :

Latent heat of vaporization : It is defined as the amount of heat energy released or absorbed when the liquid converted to vapor at atmospheric pressure at its boiling point.

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$q=L\times m$

where,

q = heat = 2000 kJ = $2\times 10^6J$ (1 kJ = 1000 J)

L = latent heat of vaporization of water = $2.25\times 10^6J/kg$

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Now put all the given values in the above formula, we get:

$2\times 10^6J=(2.25\times 10^6J/kg)\times m$

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3 0

4 years ago

as an aid in understanding this problem. The drawing shows a positively charged particle entering a 0.61-T magnetic field. The p

miv72 [106K]

Answer:

E = 420.9 N/C

Explanation:

According to the given condition:

$Net\ Force = 2(Magnetic\ Force)\\Electric\ Force - Magnetic\ Force = 2(Magnetic\ Force)\\Electric\ Force = 3(Magnetic\ Force)\\qE = 3qvBSin\theta\\E = 3vBSin\theta$

where,

E = Magnitude of Electric Field = ?

v = speed of charge = 230 m/s

B = Magnitude of Magnetic Field = 0.61 T

θ = Angle between speed and magnetic field = 90°

Therefore,

$E = (3)(230\ m/s)(0.61\ T)Sin90^o$

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3 years ago