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3 years ago

How much work does a 50.0kg person do in walking up one flight of stairs, equivalent to 3.0m?

Physics

1 answer:

Elena-2011 [213]3 years ago

8 0

Answer:

1470J

Explanation:

Given parameters:

Mass of the person = 50kg

height = 3m

Unknown:

Work done = ?

Solution:

To solve this problem, we use the expression below:

Work done = mass x acceleration due gravity x height

So;

Work done = 50 x 9.8 x 3 = 1470J

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Two forces are applied to a tree stump to pull it out of the ground. Force A has a magnitude of 2410 newtons (N) and points 36.0

Anarel [89]

Answer:

The magnitude of the resultant force is 6201 N

The direction of the resultant force is 72°

Explanation:

Please find the attached file for explanation;

8 0

3 years ago

A ball dropped from a height of 50 meters, Determine the speed of the ball after 3 seconds

Alex17521 [72]

16.7 m/s

To determine the speed we use the formula: Distance ÷ Time so, 50 ÷ 3 = 16.66... ( rounded off to 1.d.p is 16.7).

8 0

4 years ago

A proton is released from rest at the positive plate of a parallelplatecapacitor. It crosses the capacitor and reaches the negat

Triss [41]

Answer:

2.1406 × $10^6$ m/sec

Explanation:

we know that energy is always conserved

so from the law of energy conservation

$qV=\frac{1}{2}mv^2$

here V is the potential difference

we know that mass of proton = 1.67× $10^{-27}$ kg

we have given speed =50000m/sec

so potential difference $V=\frac{\frac{1}{2}\times 1.67\times 10^{-27}50000^2}{1.6\times 10^{-19}}=13.045$

now mass of electron =9.11× $10^{-31}$

so for electron

$\frac{1}{2}\times 9.11\times 10^{-31}v^2=1.6\times 10^{-19}\times 13.045=2.1406\times 10^6 m/sec$

so the velocity of electron will be 2.1406× $10^6$ m/sec

4 0

3 years ago

A car is traveling at a speed of 45 km/h into town. It takes the car 2 hours to get there. How far has the car traveled?

hjlf

Answer:

90 km

Explanation:

45 km per hr

2 hrs

45 x 2 = 90

90 km/2 hrs

Hope this helps!

7 0

3 years ago

Read 2 more answers

What is the energy difference between parallel and antiparallel alignment of the z component of an electron's spin magnetic dipo

Readme [11.4K]

Answer:

$\Delta U= 4.8204\times10^{-24} J$

Explanation:

The difference between parallel and anti parallel alignment of the z component of an electron's spin magnetic dipole moment is given by

$U_1-U_2= (-\mu Bcos(\theta_2))-(-\mu Bcos(\theta_1))$

where μ= dipole moment B= strength of magnetic field and θ= angle between direction of magnetic field and dipole

here θ_2 and θ_1 are 180 and 0° respectively.

$U_1-U_2= (\mu B)-(-\mu B)$

$U_1-U_2= 2\mu B$

here μ is bohr magnetron or magnetic moment of an electron = 9.27×10^{-24}

put this value we get

$U_1-U_2= 2\times 9.27\times10^{-24}(0.26)$

$\Delta U= 4.8204\times10^{-24} J$

3 0

3 years ago