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yan [13]
3 years ago
6

Expresa 15 Mm en mm Expresa 5 Tm en nm

Physics
2 answers:
Anastasy [175]3 years ago
7 0

Answer:

What is this on?

Explanation:

katrin2010 [14]3 years ago
5 0
Is this math or something
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A chair of weight 70.0 N lies atop a horizontal floor; the floor is not frictionless. You push on the chair with a force of F =
Annette [7]

Answer:

94.67 N

Explanation:

Consider a free body diagram with force, F of 41 N applied at an angle of 37 degrees while the weight acts downwards. Resolving the force into vertical and horizontal components, we obtain a free body diagram attached.

At equilibrium, normal reaction is equal to the sum of the weight and the vertical component of the force applied. Applying the condition of equilibrium along the vertical direction.  

\begin{array}{l}\\\Sigma {F_y} = 0\\\\N - W - F\sin \theta = 0\\\\N = W + F\sin \theta \\\end{array}

Substituting 70 N for W, 41 N for F and \theta for 37 degrees

N=70+41sin37=94.67441595  N and rounding off to 2 decimal places

N=94.67 N

​

6 0
4 years ago
A proton has a magnetic field due to its spin on its axis. the field is similar to that created by a circular current loop 0.650
Aloiza [94]

Answer:

\tau=3.48*10^{-26}Nm  

Explanation:

The torque equation is given by:

\tau=IABsin(\theta)

Where:

  • I is the current
  • A is the area of the loop (A=πR²)
  • θ is the angle between the normal vector of A and B, in this case it is 90 degrees

So:

\tau=1.05*10^{4}*\pi *(0.65*10^{-15})^{2}*2.5  

Therefore the torque is:

\tau=3.48*10^{-26}Nm    

I hope it helps you!

3 0
3 years ago
Read 2 more answers
Describe the objects that make up Saturn's rings. Your answer should include the range of sizes of objects in the rings, and the
aniked [119]
Saturn's rings are made of billions of pieces of ice, dust and rocks. Some of these particles are as small as a grain of salt, while others are as big as houses.
4 0
3 years ago
If the truck has a mass of 2000 kilograms, what is its momentum
bija089 [108]
<span>Your answer will be 70,000 kgm/s</span>
8 0
3 years ago
(A star if you answer this question) A school bus is traveling at 11.1 m/s and has a
12345 [234]

\mathfrak{\huge{\pink{\underline{\underline{AnSwEr:-}}}}}

Actually Welcome to the Concept of the Kinematics in real world.

So, as given here, we have to find the Mass of the bus from the given momentum, so we get as,

P = m * V

momentum = mass * velocity

here, P= 152625 kgm/s and v= 11.1 m/s

so substituting we get as,

m = 152625 ÷ 11.1 => 13,750 kg

hence,the mass of the bus is 13,750 kg.

3 0
3 years ago
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