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3 years ago

A rectangle measures 2 1/5 inches by 2 4/5 inches. What is its area?

Mathematics

1 answer:

antiseptic1488 [7]3 years ago

6 0

Answer:

Step-by-step explanation:

20+30?esa es la respuesta

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Solve In 2x + In 2=0

irakobra [83]

Solving $ln(2x)+ln(2)=0$ we get, $x=\frac{1}{4}$

Step-by-step explanation:

We need to solve: $ln(2x)+ln(2)=0$

Solving:

$ln(2x)+ln(2)=0$

Adding -ln(2) on both sides:

$ln(2x)+ln(2)-ln(2)=0-ln(2)$

$ln(2x)=-ln(2)$

Using logarithmic rule: if $log_a b =c\,\,then\,\, b=a^c$

So,

$2x=e^{-ln(2)}$

Simplifying:

$2x=(e^{ln(2)})^{-1}\\e^{ln(2)}=2\\2x=(2)^{-1}\\2x=\frac{1}{2} \\x=\frac{1}{2x2}\\x=\frac{1}{4}$

So, Solving $ln(2x)+ln(2)=0$ we get, $x=\frac{1}{4}$

Keywords: Logarithms

Learn more about Logarithms at:

#learnwithBrainly

4 0

3 years ago

Mary ate 5 slices of pie. Arther ate 2 slices. If Mary ate 5/10 of the pie and all the slices werethe same size, what fraction o

viktelen [127]

5/10 +2/10= 7/10 10/10-7/10= 3/10
Your answer is 3/10

4 0

3 years ago

Read 2 more answers

Solve this step by step using the quadratic function y=x^2 +x+2

Ne4ueva [31]

Answer:

x=+ $\frac{\sqrt{4y-7}-1 }{2}$

Step-by-step explanation:

Quadratic function =( -b+ $\sqrt{b^2+4ac}$ )/2a

x^2+x+2-y=0

x=-1+ $\sqrt{1^2-4(2-y)}$ /2

x=-1+ $\sqrt{4y-7}$ /2

x=+ $\frac{\sqrt{4y-7}-1 }{2}$

Pretty sure this is right. Would appreciate a brainliest

3 0

3 years ago

Geometry!!!!!!!!!!!!!!!!!!!!!!!!

Stella [2.4K]

Given:

Given that O is the center of the circle.

The radius of the circle is 3 m.

The measure of ∠AOB is 30°

We need to determine the length of the major arc ACB

Measure of major ∠AOB:

The measure of major angle AOB can be determined by subtracting 360° and 30°

Thus, we have;

$Major \ \angle AOB=360-30$

$Major \ \angle AOB=330^{\circ}$

Thus, the measure of major angle is 330°

Length of the major arc ACB:

The length of the major arc ACB can be determined using the formula,

$m \widehat{ACB}=(\frac{\theta}{360})2 \pi r$

Substituting r = 3 and $\theta=330$ , we get;

$m \widehat{ACB}=(\frac{330}{360})2 \pi (3)$

$m \widehat{ACB}=\frac{1980}{360}\pi$

$m \widehat{ACB}=5.5 \pi$

Thus, the length of the major arc ACB is 5.5π m

8 0

3 years ago

CAN SOMEONE PLEASE HELP! FOR BRAINLIEST!!!

julsineya [31]

Answer:

3*3*3 first one

Step-by-step explanation:

4 0

3 years ago