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madreJ [45]
3 years ago
5

Use Pascal’s Triangle to expand the binomial. (8v + s)5

Mathematics
2 answers:
anastassius [24]3 years ago
8 0
Check the attached file for the solution.

Ainat [17]3 years ago
3 0

Answer: 1. B) -6, -2

2. A) 7 - square root 3, 2 + square root 6

3. B) 1, 3/2, +- 5i

4. D) s^5 + 40s^4v + 640s^3v^2 + 5,120s^2v^3 + 20,480sv^4 + 32,768v^5

5. B) y= x^3 + 4x -2x - 5

6. C) 7.5

7. A) 1

8. D) y=x^4-6x^3+6x^2-6x+5

Step-by-step explanation: 100% :)

You might be interested in
15x-7=2+12x I need help with this
Amanda [17]

Answer:

\huge{ \boxed{ \bold{ \tt{x = 3}}}}

<h3>♁ Question : Solve for x</h3>
  • 15x - 7 = 2 + 12x

<h3>♁ Step - by - step explanation</h3>
  • \text{15x - 7 = 2 + 12x}

Move 12x to L.H.S ( Left Hand Side ) and change it's sign

➛\sf{15x - 12x - 7 = 2}

Move 7 to R.H.S ( Right Hand Side) and change it's sign

➛\sf{15x - 12x = 2 + 7}

Subtract 12x from 15x

Remember that only coefficients of like terms can be added or subtracted.

➛\sf{3x = 2 + 7}

Add the numbers : 2 and 7

➛\sf{3x = 9}

Divide both sides by 3

➛ \sf{ \frac{3x}{3}  =  \frac{9}{3}}

➛ \boxed{ \bold{ \sf{x = 3}}}

The value of x is \boxed{ \sf{3}}

✄ ✄ ✄ ✄ ✄ ✄ ✄ ✄ ✄ ✄ ✄ ✄ ✄ ✄ ✄

☄ Now, let's check whether the value of x is 3 or not!

<h3>☥ Verification :</h3>

\sf{15x - 7 = 2 + 12x}

\dashrightarrow{ \sf{15 \times 3 - 7 = 2 + 12 \times 3}}

\dashrightarrow{ \sf{45 - 7 = 2 + 36}}

\dashrightarrow{ \sf{38 = 38}}

L.H.S = R.H.S ( Hence , the value of x is 3 ).

✄ ✄ ✄ ✄ ✄ ✄ ✄ ✄ ✄ ✄ ✄ ✄ ✄ ✄ ✄

<h3>✒ Rules for solving an equation :</h3>
  • If an equation contains fractions ,multiply each term by the L.C.M of denominators.
  • Remove the brackets , if any.
  • Collect the terms with the variable to the left hand side and constant terms to the right hand side by changing their sign ' + ' into ' - ' and ' - ' into ' + ' .
  • Simplify and get the single term on each side.
  • Divide each side by the coefficient of variable and then get the value of variable.

Hope I helped!

Have a wonderful time ! ツ

~TheAnimeGirl

5 0
3 years ago
-7 (-6) + 17 help plz
Elden [556K]

Answer: 59

Step-by-step explanation:

-7 (-6) + 17  (multiply -7 and -6)  

= 42+17      (simplify)

=59

3 0
3 years ago
Which phrase matches the algebraic expression below?
Stella [2.4K]

Answer:

O Two times x minus seven plus ten

8 0
3 years ago
A pair of shoes cost $38. The sales tax rate is 7%. Find the total cost.
Valentin [98]

Answer:

69

Step-by-step explanation:

nice

3 0
3 years ago
A certain forest covers an area of
iVinArrow [24]

Answer:

2598 square kilometers

Step-by-step explanation:

Hello

Step 1

year one

using a rule of three is possible to find how much is 8.75 od 4500 km2

Let

if

4500 km2  ⇒ 100$

x?km2         ⇒8.75

do the relation and isolate x

4500:100\\x:8.75\\\frac{4500}{100}=\frac{x}{8.75}\\x=\frac{4500*8.75}{100} \\x=393.75\\

at the end of the year one, the area will be

4500-393.75=4106.25

this will be the initial area for the year 2.

Step 2

repite the step 1 with area initial =4106.25 km2

4106.25 km2  ⇒ 100$

x?km2         ⇒8.75

do the relation and isolate x

4106.25:100\\x:8.75\\\frac{4106.25}{100}=\frac{x}{8.75}\\x=\frac{4106.25*8.75}{100} \\x=359.29\\

at the end of the year 2, the area will be

4106-359.29=3746.70

this will be the initial area for the year 3.

Step 3

repite the step 1 with area initial =4106.25 km2

3746.70 km2  ⇒ 100$

x?km2         ⇒8.75

do the relation and isolate x

3746.70:100\\x:8.75\\\frac{3746.70}{100}=\frac{x}{8.75}\\x=\frac{3746.7*8.75}{100} \\x=327.83\\

at the end of the year 3, the area will be

3746.70-327.83=3419.09

this will be the initial area for the year  4.

Step 4

year four

repite the step 1 with area initial =3419.09 km2

3419.09 km2  ⇒ 100$

x?km2         ⇒8.75

do the relation and isolate x

3419.09:100\\x:8.75\\\frac{3419.09}{100}=\frac{x}{8.75}\\x=\frac{3419.09*8.75}{100} \\x=299.17\\

at the end of the year 4, the area will be

3419.09-299.173=3119.82

this will be the initial area for the year  5.

Step 5

year five

repite the step 1 with area initial =3119.82 km2

3119.82 km2  ⇒ 100$

x?km2         ⇒8.75

do the relation and isolate x

3119.82:100\\x:8.75\\\frac{3119.82}{100}=\frac{x}{8.75}\\x=\frac{3119.82*8.75}{100} \\x=272.99\\

at the end of the year 5, the area will be

3119.82-272.99=2846.92

this will be the initial area for the year  6.

Step 6

year six

repite the step 1 with area initial =2846.92km2

2846.92 km2  ⇒ 100$

x?km2         ⇒8.75

do the relation and isolate x

2846.92:100\\x:8.75\\\frac{2846.92}{100}=\frac{x}{8.75}\\x=\frac{2846.92*8.75}{100} \\x=249.10\\

at the end of the year six, the area will be

2846.92-249.10=2597.82 square kilometers

Have a great day.

8 0
3 years ago
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