AVERAGE between 90 and 100%
means not including 90 and 100% but not including 90 or 100%
average=(sum of values in set)/(how many values in the set)
so
4 exams, so there are 4 values
average=(sum)/4
the sum is the known+unknwon
sum=76+99+86+x
so
90<span><</span>average and average <span><</span>100
or
90<span><</span>average<span><</span>100
lets say average=a
a=sum/number
a=(76+99+86+x)/4
90<(76+99+86+x)/4<100
90<(76+99+86+x)/4 and (76+99+86+x)/4<100
solve each for x and find intersection
90<span><</span>(76+99+86+x)/4
times 4 both sides
360<span><</span>261+x
minus 261 both sides
99<span><</span>x
(76+99+86+x)/4<u><</u>100
times 4 both sides
261+x<u><</u>400
minus 261 both sides
x<u><</u>139
so
99<u><</u>x<u><</u>139
since max score is 100
99<u><</u>x<u><</u>100
interval notaion is
[99,100]
answer is 2nd one
Answer:
y = -1/5x + 19/5 or
x + 5y = 19.
Step-by-step explanation:
The slope of the line (m) = (5-3) / (-6-4)
= -1/5.
Using the point-slope form of the equation of a line:
y - y1 = m(x - x1) m = -1/5. x1 = 4 and y1 = 3 , so:
y - 3 = -1/5(x - 4)
y - 3 = -1/5x + 4/5
y = -1/5x + 19/5 which is the equation in slope-intercept form.
Converting to standard form ( multiplying by 5):
5y = -x + 19
x + 5y = 19.
Answer:
It would be inverse variation because inverse variation is when either x increases and y decreases, or y increases and x decreases.
In your case it is where x increases and y decreases
Hope this helps ;)
Step-by-step explanation:
X = 7 and x = 1
Two solutions were found.