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daser333 [38]
3 years ago
15

Someone help I really need it.

Mathematics
2 answers:
yanalaym [24]3 years ago
7 0

C

12 = x

12 times 12 = 144

NeX [460]3 years ago
6 0

Answer:

c

Step-by-step explanation:

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Please help me ASAP. For homework due right now
sveta [45]

Answer:

at least 20 rows.

Step-by-step explanation:

when you add the students, teachers, and chaperones, it comes to 159. then you divide 159 by the number of seats each row has, so 159/8 = 19.875, you would have to round to the nearest whole number so 20 should be correct.

5 0
3 years ago
Solve the following systems of equations 2a+4b+c=5 ; a-4b=-6 ; 2b+c=7.
SOVA2 [1]

Answer:

a = -2

b = 1

c = 5

Step-by-step explanation:

Given:

2a + 4b + c = 5 ............(1)

a - 4b = - 6

or

a = 4b - 6 .............(2)

2b + c = 7

or

c = 7 - 2b   ...........(3)

substituting 2 and 3 in  1, we get

2(4b - 6 ) + 4b + (7 - 2b) = 5

or

8b - 12 + 4b + 7 - 2b = 5

or

10b - 5 = 5

or

b = 1

substituting b in 2, we get

a = 4(1) - 6

or

a = -2

substituting b in 3, we get

c = 7 - 2(1)

or

c = 5

thus,

a = -2

b = 1

c = 5

8 0
3 years ago
Arthur starts his first workout routine by doing 10 push-ups. Each workout after the first, he plans to do 2 more push-ups than
Reptile [31]

Answer:

50

Step-by-step explanation:

10 + (20x2) = 50

4 0
3 years ago
49 PTS
ANTONII [103]

so i am sure you know that 1 hour is sixty minutes

so this is how it woulds

10/1 * 60/1 = 600 minutes

so that means that 10 hours would be equal to 600 minutes

then add on the 39 minutes

639

BUT WAIT there are the seconds

24/1 * 1/60 = 0.4

so 24 seconds is 0.4 (40%) of a minute

so it would take 639.4 minutes for saturn to make a full rotation

i hope this helped and please vote me for brainliest! have a nice day!

8 0
3 years ago
Read 2 more answers
On Mars the acceleration due to gravity is 12 ft/sec^2. (On Earth, gravity is much stronger at 32 ft/sec^2.) In the movie, John
insens350 [35]

Solution :

Given initial velocity, v= 48 ft/s

Acceleration due to gravity, g = $12\ ft/s^2$

a). Therefore the maximum height he can jump on Mars is

     $H_{max}=\frac{v^2}{2g}$

     $H_{max} = \frac{(48)^2}{2 \times 12}$

               = 96 ft

b). Time he can stay in the air before hitting the ground is

   $T=\frac{2v}{g}$

  $T=\frac{2 \times 48}{12}$

     = 8 seconds

c).  Considering upward motion as positive direction.

     v = u + at

We find the time taken to reach the maximum height by taking v = 0.

     v = u + at

     0 = 16 + (12) t

     $t=\frac{16}{12}$

        $=\frac{4}{3} \ s$

We know that, $S=ut + \frac{1}{2}at^2$

Taking t =  $=\frac{4}{3} \ s$  , we get

$S=16 \times\frac{4}{3} + \frac{1}{2}\times(-12) \times \left(\frac{4}{3}\right)^2$

$S=\frac{32}{3}$  feet

Thus he can't reach to 100 ft as it is shown in the movie.

d). For any jump whose final landing position will be same of the take off level, the final velocity will be the initial velocity.

Therefore final velocity is = -16 ft/s

3 0
3 years ago
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