I have no idea so just solve it for me

A wooden bench was originally priced at $50 but went on sale for 20% off. If Presley bought the wooden bench and paid a 5% sales

Savatey [412]

Answer:

$42.00

Step-by-step explanation:

20% OF 50 = 40

Before Tax Price: $40.00

Sale Tax: 5.00% or $2.00

After Tax Price: $42.00

5 0

3 years ago

Read 2 more answers

Kate bought 3 used CDs and 1 used DVD at the bookstore. Her friend Joel bought 2 used CDs and 2 used DVDs at the same store. If

natka813 [3]

Answer:

Cost of 1 DVD is $6.5

Cost of one CD is $4.5

Combine cost of one DVD and CD is $11

Step-by-step explanation:

Given :

Kate bought 3 used CDs and 1 used DVD at the bookstore.

Her friend Joel bought 2 used CDs and 2 used DVDs at the same store.

Kate spent $20

Joel spent $22

To Find : the cost of a used CD and a used DVD

Solution :

Let cost of 1 used CDs be $x

Let cost of 1 used DVDs be $y

Cost of 3 used CDs = $3x

Cost of 2 used CDs = $2x

Cost of 2 used DVDs = $2y

Kate bought 3 used CDs and 1 used DVD at the bookstore.

She spent $20

So, equation becomes :

⇒ $3x+y=20$ ---(a)

Joel bought 2 used CDs and 2 used DVDs. she spent $22.

So, equation becomes:

⇒ $2x+2y=22$ --(b)

Now solve (a) and (b) to determine the value of x and y

We will use substitution method

Substitute the value of x from (b) in (a)

$3(\frac{22-2y}{2} )+y=20$

$33-3y+y=20$

$33-2y=20$

$33-20=2y$

$13=2y$

$\frac{13}{2} =y$

$6.5 =y$

Thus cost of 1 DVD is $6.5

Now substitute this value of y in b to get value of x

⇒ $2x+2(6.5)=22$

⇒ $2x+13=22$

⇒ $2x=22-13$

⇒ $2x=9$

⇒ $x=\frac{9}{2}$

⇒ $x=4.5$

Thus the cost of one CD is $4.5

Hence the combine cost of one DVD and CD = $6.5+ $4.5=$11

6 0

4 years ago

Cher wraps 40 presents in 2 hours. At that rate, how many presents would she wrap in 15 minutes

gavmur [86]

Answer:

5 presents

Step-by-step explanation:

40 presents in 2 hours

20 presents in 1 hour (divide by 2)

20 presents in 60 minutes ( 1 hour is 60 minutes )

5 presents in 15 minutes ( divide by 4)

6 0

3 years ago

Select all the expressions that are equivalent to (2)^n+³

eimsori [14]

Answer:

The expressions which equivalent to $(2)^{n+3}$ are:

$4(2)^{n+1}$ ⇒ B

$8(2)^{n}$ ⇒ C

Step-by-step explanation:

Let us revise some rules of exponent

$a^{m}$ × $a^{m}$ = $a^{m+n}$
$(a^{m})^{n}$ = $a^{m*n}$

Now let us find the equivalent expressions of $(2)^{n+3}$

A.

∵ 4 = 2 × 2

∴ 4 = $2^{2}$

∴ $(4)^{n+2}$ = $(2^{2})^{n+2}$

- By using the second rule above multiply 2 and (n + 2)

∵ 2(n + 2) = 2n + 4

∴ $(4)^{n+2}$ = $(2)^{2n+4}$

B.

∵ 4 = 2 × 2

∴ 4 = 2²

∴ $4(2)^{n+1}$ = 2² × $(2)^{n+1}$

- By using the first rule rule add the exponents of 2

∵ 2 + n + 1 = n + 3

∴ $4(2)^{n+1}$ = $(2)^{n+3}$

C.

∵ 8 = 2 × 2 × 2

∴ 8 = 2³

∴ $8(2)^{n}$ = 2³ × $(2)^{n}$

- By using the first rule rule add the exponents of 2

∵ 3 + n = n + 3

∴ $8(2)^{n}$ = $(2)^{n+3}$

D.

∵ 16 = 2 × 2 × 2 × 2

∴ 16 = $2^{4}$

∴ $16(2)^{n}$ = $2^{4}$ × $(2)^{n}$

- By using the first rule rule add the exponents of 2

∵ 4 + n = n + 4

∴ $16(2)^{n}$ = $(2)^{n+4}$

E.

$(2)^{2n+3}$ is in its simplest form

The expressions which equivalent to $(2)^{n+3}$ are:

$4(2)^{n+1}$ ⇒ B

$8(2)^{n}$ ⇒ C

3 0

4 years ago

The distance d, in centimeters, that a diving board bends below its resting position when you stand at its end is dependent on y

kaheart [24]

Answer:

d(1) = -3 and d(2)= -28

Step-by-step explanation:

Given that the distance d, in centimeters, that a diving board bends below its resting position when you stand at its end is dependent on your distance x, in meters, from the stabilized point

$d(x)=-4x^3+x^2$

For finding out the distances for x=1 and x=2

let us substitute 1 and 2 for x

$d(1) = -4(1^3)+1^2 = -3$

$d(2) = -4(2^3)+2^2 \\= -28$

d(1) = -3 and d(2)= -28

3 0

3 years ago